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Answer:</h2>
<h3>From the equation it is evident that 2 moles of Sodium metal produces 1 mole of hydrogen gas.</h3><h3>At STP 1mole of any gas occupies a volume of 22.4 litres.</h3><h3>Therefore, 7.80 gives---(7.80x1)/22.4 moles = 0.3482 moles</h3><h3>Since the mole ratio of Sodium to hydrogen is 2:1, then the number of moles of sodium that reacted is given by the following expression.</h3><h3>(0.3482 * 2) / 1 moles which gives 0.6964 moles.</h3><h3>The atomic mass of sodium is 23 thus the mass of sodium that reacted is given by:</h3><h3>mass=no. of Monogram</h3><h3>0.6964 * 23 = 16.02 grams.</h3><h2>
Explanation:</h2><h3>please mark me brainlist</h3>
<span>6 + x = 12. To evaluate an algebraic expression, you have to substitute a number for each variable and perform the arithmetic operations. In the example above, the variable x is equal to 6 since 6 + 6 = 12. If we know the value of our variables, we can replace the variables with their values and then evaluate the expression.</span>
Because its in group one....which only lose or gain electrons.....thus it will only have oneelectron to fulfill its octect rule
Answer:
MgSO4.7H2O
Explanation:
Let the formula for the hydrated magnesium sulphate be MgSO4.xH2O
Mass of the hydrated salt (MgSO4.xH2O) = 12.845g
Mass of anhydrous salt (MgSO4) = 6.273g
Mass of water molecule(xH2O) = Mass of the hydrated salt — Mass of anhydrous salt = 12.845 — 6.273 = 6.572g
Now,we can obtain the number of mole of water molecule present in the hydrated salt as follows:
Molar Mass of hydrated salt (MgSO4.xH2O) = 24 + 32 + (16x4) + x(2 + 16) = 24 + 32 + 64 + x(18) = 120 + 18x
Mass of xH2O/ Molar Mass of MgSO4.xH2O = Mass of water / mass of hydrated salt
18x/120 + 18x = 6.572/12.845
Cross multiply to express in linear form
18x x 12.845 = 6.572(120 + 18x)
231.21x = 788.64 + 118.296x
Collect like terms
231.21x — 118.296x = 788.64
112.914x = 788.64
Divide both side by 112.914
x = 788.64 /112.914
x = 7
Therefore the formula for the hydrated salt (MgSO4.xH2O) is MgSO4.7H2O
Answer:
hco I believe
Explanation:
Pretty sure about this, when do you need to put it in?