1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
pentagon [3]
3 years ago
13

Jessie received the following scores on her math tests this year. (45, 65, 70, 80, 85, 100) Suppose the teacher removes the lowe

st and highest scores. (65, 70, 80, 85) What are the interquartile ranges of Jessie’s original scores and her new scores?
Mathematics
2 answers:
notsponge [240]3 years ago
7 0
Original scores :
45,65,70,80,85,100
IQR = 85 - 65 = 20

new scores :
65,70,80,85
IQR = (80 + 85)/2 - (65 + 70)/2 = 82.5 - 67.5 = 15
vesna_86 [32]3 years ago
7 0

Answer:

Interquartile ranges of Jessie’s original scores = 20

Interquartile ranges of Jessie’s new scores = 15

Step-by-step explanation:

Interquartile range IQR = Higher quartile (Q3) - lower quartile (Q1)

Where Q3 is the mid-value of the second half of a dataset and

Q1 is the mid-value of the first half of a dataset.

Original score = 45, 65, 70, 80, 85, 100

Q1 of original score:

First half of original score = 45, 65, 70

Therefore Q1 = 65

Q3 of original score:

Second half of original score = 80, 85, 100

Therefore Q3 = 85

:. Interquartile range IQR of original score = Q3 of original score - Q1 of original score

:. IQR = 85 - 65 = 20

New score = 65, 70, 80, 85

Q1 of new score:

First half of new score = 65, 70

Therefore Q1 = (65+70)/2 = 67.5

Q3 of new score:

Second half of new score = 80, 85

Therefore Q3 = (80 + 85)/2 = 82.5

:. Interquartile range IQR of new score = Q3 of new score - Q1 of new score

:. IQR = 82.5 - 67.5 = 15

Therefore:

Interquartile ranges of Jessie’s original scores = 20

Interquartile ranges of Jessie’s new scores = 15

You might be interested in
A farmer has a square garden that has an area of 100 feet squared. He needs to
stellarik [79]

Answer:

40ft

Step-by-step explanation:

The shape of the garden (square) tells you that both the length and the width of the garden are the same measure.

If the area is 100sqft, you can determine that side * side = 100. To find this answer, you can take the square root of 100. side=10, because 10 * 10= 100 (the area).

Now, we know that each side measures 10 feet. Try drawing and labeling a picture to help you visualize the garden. Next, label each side of the square garden 10ft.  To find the feet of fencing is needed to enclose the garden,

We need to find the perimeter, so we can calculate

10ft * 4 sides = 40 feet of fencing.

5 0
3 years ago
In the first quadrant you start at (7,3) and move 5 unit left
AveGali [126]

Answer:

That would be (2,3)

Step-by-step explanation:

When we're moving left in the coordinate plane, we are subtracting the x-coordinate by how much distance we move.

In this case, 7-5=2, so the new x-coordinate is 2, but the y-coordinate doesn't change since we're going horizontally and not vertically.

7 0
3 years ago
Mike has 8 feet of rope . How many inches of rope does he have.
Ostrovityanka [42]
96 in. of rope.
8x12=96
4 0
3 years ago
Read 2 more answers
Graph for f(x)=6^6 and f(x)=14^x
zlopas [31]

Graph Transformations

There are many times when you’ll know very well what the graph of a

particular function looks like, and you’ll want to know what the graph of a

very similar function looks like. In this chapter, we’ll discuss some ways to

draw graphs in these circumstances.

Transformations “after” the original function

Suppose you know what the graph of a function f(x) looks like. Suppose

d 2 R is some number that is greater than 0, and you are asked to graph the

function f(x) + d. The graph of the new function is easy to describe: just

take every point in the graph of f(x), and move it up a distance of d. That

is, if (a, b) is a point in the graph of f(x), then (a, b + d) is a point in the

graph of f(x) + d.

As an explanation for what’s written above: If (a, b) is a point in the graph

of f(x), then that means f(a) = b. Hence, f(a) + d = b + d, which is to say

that (a, b + d) is a point in the graph of f(x) + d.

The chart on the next page describes how to use the graph of f(x) to create

the graph of some similar functions. Throughout the chart, d > 0, c > 1, and

(a, b) is a point in the graph of f(x).

Notice that all of the “new functions” in the chart di↵er from f(x) by some

algebraic manipulation that happens after f plays its part as a function. For

example, first you put x into the function, then f(x) is what comes out. The

function has done its job. Only after f has done its job do you add d to get

the new function f(x) + d. 67Because all of the algebraic transformations occur after the function does

its job, all of the changes to points in the second column of the chart occur

in the second coordinate. Thus, all the changes in the graphs occur in the

vertical measurements of the graph.

New How points in graph of f(x) visual e↵ect

function become points of new graph

f(x) + d (a, b) 7! (a, b + d) shift up by d

f(x) Transformations before and after the original function

As long as there is only one type of operation involved “inside the function”

– either multiplication or addition – and only one type of operation involved

“outside of the function” – either multiplication or addition – you can apply

the rules from the two charts on page 68 and 70 to transform the graph of a

function.

Examples.

• Let’s look at the function • The graph of 2g(3x) is obtained from the graph of g(x) by shrinking

the horizontal coordinate by 1

3, and stretching the vertical coordinate by 2.

(You’d get the same answer here if you reversed the order of the transfor-

mations and stretched vertically by 2 before shrinking horizontally by 1

3. The

order isn’t important.)

74

7:—

(x) 4,

7c’

‘I

II

‘I’

-I

5 0
3 years ago
A 12 1/2 mile stretch of road needs repaving . A company bids on the repaving project saying they could replace 2 1/4 miles of r
Nataly [62]

2 1/4 miles => 1 week

1 mile => 1 ÷ 9/4

( 9/4 is an improper fraction of 2 1/4 )

12 1/2 miles => ( 1 ÷ 9/4 ) × 25/2

= 50/9

= 5 5/9 weeks

( 25/2 is an improper fraction of 12 1/2 )

Therefore, it will take 5 5/9 weeks for the company to replace the stretch of road.

( you can round it off to 6 weeks if the qn specify to give to the nearest whole number )

8 0
3 years ago
Other questions:
  • What is the value of the expression: x - 3y
    5·1 answer
  • Please help me <33333
    6·1 answer
  • What is this equation in point-slope form?
    12·1 answer
  • A researcher posts an online advertisement offering $25 in exchange for participation in a short study. The researchers accepts
    15·1 answer
  • It takes one student 8 hours to wash all of the cars at a school car wash. If 6
    5·1 answer
  • Help me please
    13·1 answer
  • If the length of a diagonal of a square is 10 feet what is the length of a side of the square
    11·1 answer
  • Please help:)) will give brainliest:)
    15·1 answer
  • How to learn math faster?
    13·1 answer
  • It’s the start of a new football season and my favorite team, the WACO Hawks, is looking good! They won their first
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!