Please see the picture Line A , B , C , or D ? Help me see the picture

The least common multiples

Talja [164]

For second one the answer is 14

8 0

2 years ago

Read 2 more answers

What is the principal square root of StartRoot 13 Superscript 2 EndRoot.? 13 26 169 676

9966 [12]

Answer:

13

Step-by-step explanation:

If I read this correctly:

you want to know the square root of 13²?

That would be 13

3 0

3 years ago

The diameter of fishing line varies. Fishing lines can have a diameter as small as 2 x 102 inch and as large as 6 x 10-2 inch. H

Reil [10]

Answer:
3 times

Explanation:
We know that:
small diameter = 2 * 10^-2 in
large diameter = 6 * 10^-2 in

We want to know how many times larger is the thin diameter compared to the large one.
We will do this as follows:
large diameter = k * small diameter
where k is the number of times that we want to find
6 * 10^-2 = k * 2 * 10^-2
k = (6 * 10^-2) / (2 * 10^-2)
k = 3

This means that the large diameter is 3 times the small one.

Hope this helps :)

4 0

3 years ago

The general solution of 2 y ln(x)y' = (y^2 + 4)/x is

Sav [38]

Replace $y'$ with $\dfrac{\mathrm dy}{\mathrm dx}$ to see that this ODE is separable:

$2y\ln x\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{y^2+4}x\implies\dfrac{2y}{y^2+4}\,\mathrm dy=\dfrac{\mathrm dx}{x\ln x}$

Integrate both sides; on the left, set $u=y^2+4$ so that $\mathrm du=2y\,\mathrm dy$ ; on the right, set $v=\ln x$ so that $\mathrm dv=\dfrac{\mathrm dx}x$ . Then

$\displaystyle\int\frac{2y}{y^2+4}\,\mathrm dy=\int\dfrac{\mathrm dx}{x\ln x}\iff\int\frac{\mathrm du}u=\int\dfrac{\mathrm dv}v$

$\implies\ln|u|=\ln|v|+C$

$\implies\ln(y^2+4)=\ln|\ln x|+C$

$\implies y^2+4=e^{\ln|\ln x|+C}$

$\implies y^2=C|\ln x|-4$

$\implies y=\pm\sqrt{C|\ln x|-4}$

4 0

2 years ago

49x^2=-21x-2 quadratic functions

lara [203]

Answer: 49x^2=-21x-2 quadratic functions -1/7and -2/7

Step-by-step explanation:

Quadratic function:

In elementary algebra, the quadratic formula is a formula that provides the solution to a quadratic equation. There are other ways of solving a quadratic equation instead of using the quadratic formula, such as factoring, completing the square, graphing and others.

Move terms to the left side

49 $x^{2}$ =-21x-2

49 $x^{2}$ -(-21x-2) =0

Distribute

49 $x^{2}$ -(-21x-2) =0

49 $x^{2}$ +21x+2=0

Use the quadratic formula

x=(-b±√ $b^{2}$ -4ac ) / 2a

Once in standard form, identify a, b, and c from the original equation and plug them into the quadratic formula.

49 $x^{2}$ +21x+2=0

let, a=49

b=21

c=2

Replace with values in this equation

X=(-b±√ $b^{2}$ -4ac ) / 2a

Simplify

Evaluate the exponent

Multiply the numbers

Subtract the numbers

Evaluate the square root

Multiply the numbers

x=(-21±7) /98

Separate the equations

To solve for the unknown variable, separate into two equations: one with a plus and the other with a minus.Separate

x=(-21+7) /98

x=(-21-7) /98

Solve

Rearrange and isolate the variable to find each solution

x=-1/7

x=-2/7

Learn more about area here https://brainly.in/question/5597925

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3 0

1 year ago