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creativ13 [48]
3 years ago
6

Giselle graphs the function f(x) = x^2. Robin graphs the function g(x) = –x^2. How does Robin’s graph relate to Giselle’s?

Mathematics
2 answers:
valentinak56 [21]3 years ago
6 0
I graphed the functions using 1,2,3 as the value of x.

My answer would be: <span>Robin’s graph is a reflection of Giselle’s graph over the x-axis.


</span>
Karolina [17]3 years ago
5 0

Robin's graph of the function g(x)=-x^2=-f(x) is the reflection of Giselle’s graph over the x-axis.

You can think in two ways:

1. For the function y=f(x), the sign minus before f(x) change the positive values of y into negative values. For example, f(2)=4 and g(2)=-4. This means that graphs of f(x) and g(x) are symmetric across the x-axis.

2. You can simply construct the table of values

\begin{array}{rcc}   x & f(x)=x^2 & g(x)=-x^2 \\   0 & 0 & 0 \\   1 & 1 & -1 \\   -1 & 1 & -1 \\   2 & 4 & -4 \\   -2 & 4 & -4 \\   3 & 9 & -9 \\  -3 & 9 & -9 \end{array}

and plot both graphs on the coordinate plane. From this diagram it is seen that graphs are symmetric over x-axis and Robin’s graph is a reflection of Giselle’s graph over the x-axis.

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nikdorinn [45]
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Answer:

The number of knitted scarves is 10

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Step-by-step explanation:

Given as :

The cost of each knitted scarves = $50

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Total number of scarves and mitten bought = 30

The total money invested to pay for items = $1000

Let The number of knitted scarves = k

Let The number of mitten = m

<u>Now, According to question</u>

The total money invested to pay for items = cost of each knitted scarves × number of knitted scarves + cost of pairs of mittens × number of mitten

i.e $1000 = $50 × k + $25 × m

Or, 40 = 2 k + m

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Total number of scarves and mitten bought =  number of knitted scarves +  number of mitten

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Now, solving eq A and eq B

So, (2 k + m ) - ( k + m ) = 40 - 30

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Put the value of k into eq B

∵ k + m = 30

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or, m = 30 - 10

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Hence,  The number of knitted scarves is 10 and The number of knitted mitten is 20  . Answer

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Step-by-step explanation:

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7nadin3 [17]

Answer:

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Answer:

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