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3 years ago

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Mathematics

2 answers:

s2008m [1.1K]3 years ago

5 0

Answer:

Step-by-step explanation:

15 + 12 = 27

Allie would have read 27 books in total after being in the book club for 12 months.

densk [106]3 years ago

5 0

Answer:

Step-by-step explanation:

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Find the GCF of each pair of numbers.

e-lub [12.9K]

10 77 uhhh 45 dont know

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3 years ago

On percent error, if 48% is the actual and the error rate is 20%, what is the estimate?

alex41 [277]

The estimate is 57.6 %

Solution:

Given that, On percent error, 48% is the actual and the error rate is 20%

To find: Estimate

Percent error is the difference between a measured and known value, divided by the known value, multiplied by 100%

The formula for percent error is given as:

$\text { percent error }=\frac{\text {estimated value}-\text {actual value}}{\text {actual value}} \times 100$

Here given that,

percent error = 20 %

Actual = 48 %

Estimate = ?

Let "x" be the estimate

Substituting the values we get,

$20 = \frac{x-48}{48} \times 100\\\\20 \times 48 = (x-48) \times 100\\\\960 = x - 48 \times 100\\\\x - 48 = \frac{960}{100}\\\\x - 48 = 9.6\\\\x = 48 + 9.6\\\\x = 57.6$

Thus the estimate is 57.6 %

8 0

3 years ago

Helpppp help helppppppp

Yuri [45]

Answer:

56 degrees

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

How many liters of a 20% alcohol solution must be mixed with 60 liters of a 90% solution to get a 80% solution?

leva [86]

x = liters of 20% solution

Mixing the 20% solution with the 60 L of 90% solution gives a new mixture with volume (x + 60) L. Each L of the 20% solution contributes 0.2 L of alcohol and thus a total of 0.2x L of alcohol, while the 60 L of 90% solution contributes 54 L of alcohol.

We want the concentration of the new mixture to be 80%, so we require

$\dfrac{0.2x+54}{x+60}=0.8$

Solve for x:

$0.2x+54=0.8x+42$

$12=0.4x$

$\implies\boxed{x=30}$

So you will need 30 L of the 20% solution.

8 0

3 years ago

En la primera fase del proceso selectivo para Al cuerpo de profesores eliminan a cuatro novenos De los aspirantes mientras que e

irina1246 [14]

Answer:

The fraction of the applicants who have passed the two phases of the selection process is $\frac{10}{63}$ .

Step-by-step explanation:

The question is:

In the first phase of the selection process for the body of teachers they eliminate four-ninth of the applicants while in the second phase they eliminate 5/7 of those who passed the first phase. If there were 315 applicants what is the fraction of the applicants who have passed the two phases of the selection process?

The total number of applicants is

N = 315.

It is provided that 4/9th of the applicants were eliminated in the first phase.

Then the fraction of candidates who passed the first phase is:

Fraction who passed phase I = $1-\frac{4}{9}=\frac{5}{9}$

Now, it is also provided that 5/7 of those who passed the first phase were eliminated in the second phase.

Then the fraction of candidates who passed the second phase is:

Fraction who passed phase II = $1-\frac{5}{7}=\frac{2}{7}$

That is, 2/7 of the remaining applicants passed the second phase.

The fraction of the applicants who have passed the two phases is:

$\frac{5}{9}\times \frac{2}{7}=\frac{10}{63}$

Thus, the fraction of the applicants who have passed the two phases of the selection process is $\frac{10}{63}$ .

8 0

3 years ago