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inessss [21]
3 years ago
10

Many non-profit groups ask for donations during December. Do men give higher monetary donations than women in the month of Decem

ber? How should we write the alternative hypothesis? Let mum be the population mean donation for men and let muw be the population mean donation for women. please explain your answer
a. Ha: mum - muw does not equal 0
b. Ha: mum - muw = 0
c. Ha: mum - muw < 0
d. Ha: mum -muw > 0
Mathematics
1 answer:
Lelu [443]3 years ago
3 0

Answer:

For this case we want to test if do men give higher monetary donations than women in the month of December (alternative hypothesis) and the complement should be the null hypothesis. So then the sytem of hypothesis are:

Null hypothesis:\mu_m -\mu_w \leq 0

Alternative hypothesis : \mu_m -\mu_w >0

So then the best option would be:

d. Ha: mum -muw > 0

Step-by-step explanation:

Previous concepts

A hypothesis is defined as "a speculation or theory based on insufficient evidence that lends itself to further testing and experimentation. With further testing, a hypothesis can usually be proven true or false".  

The null hypothesis is defined as "a hypothesis that says there is no statistical significance between the two variables in the hypothesis. It is the hypothesis that the researcher is trying to disprove".  

The alternative hypothesis is "just the inverse, or opposite, of the null hypothesis. It is the hypothesis that researcher is trying to prove".  

Solution to the problem

For this case we want to test if do men give higher monetary donations than women in the month of December (alternative hypothesis) and the complement should be the null hypothesis. So then the sytem of hypothesis are:

Null hypothesis:\mu_m -\mu_w \leq 0

Alternative hypothesis : \mu_m -\mu_w >0

So then the best option would be:

d. Ha: mum -muw > 0

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Two number cubes are rolled sequentially. What is the probability that the first number cube shows a five and the other number c
nexus9112 [7]

The probability of first number cube shows a five and the other number cube shows an even number is \frac{1}{12}.

Solution:

Two cubes are rolled sequentially.

Sample space when two dies are rolled

                   =\left\{\begin{array}{l}{(1,1),(1,2),(1,3),(1,4),(1,5),(1,6)} \\{(2,1),(2,2),(2,3),(2,4),(2,5),(2,6)} \\{(3,1), 3(, 2),(3,3),(3,4),(3,5),(3,6)} \\{(4,1),(4,2),(4,3),(4,4),(4,5),(4,6)} \\{(5,1),(5,2),(5,3),(5,4),(5,5),(5,6)} \\{(6,1),(6,2),(6,3),(6,4),(6,5),(6,6)}\end{array}\right\}

Number of sample space = 36

Even numbers getting when two cubes rolled are 2, 4, 6.

First number cube shows a five and the other number cube shows an even number = {(5, 2), (5, 4), (5 6)}

Number of first number cube shows a five and the other number cube shows an even number = 3

Probability of first number cube shows a five and the other number cube shows an even number

                 $=\frac{\text{Number of outcomes}}{\text{Total number of sample space}} $

                $=\frac{3}{36}

                $=\frac{1}{12}

Hence, the probability of first number cube shows a five and the other number cube shows an even number is \frac{1}{12}.

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3 years ago
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