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VashaNatasha [74]
3 years ago
7

the origial price of the computer was reduced by $250 if p= the computer's original price in dollars which algebraic expression

represents the reduced price A 250+p B p-250 C 250-p or D 250p
Mathematics
2 answers:
erica [24]3 years ago
8 0

Answer:

p - 250

the original price is p, and it is reduced by 250, therefore the algebraic expression would be p - 250.

Step-by-step explanation:

Olegator [25]3 years ago
4 0

Answer:

B) p - 250

Step-by-step explanation:

Original price = p

Reduced price = p - 250.

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299,792,458 rounded to the greatest place value
andrew11 [14]

Answer:

300,000,000

Step-by-step explanation:

299,792,458

2 rounded to 9 is the answer

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3 years ago
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Answer:

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2 years ago
Factorise 12u-uv please help lol
max2010maxim [7]

Answer:

u(12-v)

Step-by-step explanation:

12u and -uv both have a factor of <em>u </em>in common, so we can pull it out to give us the factored expression u(12-v).

<em>Note on factoring:</em>

<em>Remember, it's just using the distributive property in reverse! We can get our original expression back by distributing the u to the 12 and the -v.</em>

6 0
3 years ago
7 less than the product of a number and 8, increased by a number multiplied by 2
nataly862011 [7]

The expression for 7 less than the product of a number and 8, increased by a number multiplied by 2 is 8n-7 +2n

Given :

7 less than the product of a number and 8, increased by a number multiplied by 2

We need to write the given statement in an expression

Lets 'n' be the unknown number

the product of a number and 8

Product means multiplication

the product of a number and 8 mean n times 8 that is 8n

7 less than the product of a number and 8, subtract 7 from 8n

Expression becomes 8n-7

This is increased by a number multiplied by 2

number multiplied by 2 is 2n

So the final expression for the given statement is 8n-7 +2n

Learn more : brainly.ph/question/1023996

3 0
2 years ago
Find a and b such that gcd(a, b) = 14, a &gt; 2000, b &gt; 2000, and the only prime divisors of a and b are 2 and 7.
choli [55]

Answer:

a = 2^\alpha.14 \ ,\alpha\geq 8\\b = 7^\delta.14 \ , \delta\geq 3

Step-by-step explanation:

As 2  and 7 are the only prime divisors of both a and b we know that both can be written as:

a = 2^\alpha . 7^\beta \ , \alpha ,\beta\ \in \mathbb{N}_{0}\\b = 2^\gamma . 7^\delta \ , \gamma ,\delta\ \in \mathbb{N}_{0}\\

Where \mathbb{N}_{0} is the set of all natural numbers adding the zero (careful because this part is important as I'll explain next).

We also know that 14 divides both numbers and that is actually the greatest common divisor between them. So we can rewrite a and b as follows:

a = 2^\alpha . 7^\beta.14 \ , \alpha ,\beta\ \in \mathbb{N}_{0}\\b = 2^\gamma . 7^\delta.14 \ , \gamma ,\delta\ \in \mathbb{N}_{0}\\

Why do I write them like this? Because this way is easier to observe that if \alpha and \gamma were both greater than zero, then 28 would divide both hence 14 wouldn't be their g.c.d.. Likewise, if \beta and \delta were both greater than zero, then 98 would divide both and once again, 14 wouldn't be their g.c.d.

So either of them has to be equal to zero. And then we have that

a = 2^\alpha.14 \\b = 7^\delta.14

All we have left to do is find the possible values for \alpha and \delta so that a>2000 \ , b>2000 and that only happens if \alpha\geq 8 and \delta\geq 3

8 0
3 years ago
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