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Vadim26 [7]
3 years ago
15

Sean has 4 cookies. He wants to divide the cookies among his friends so that each friend gets of a cookie. How many friends can

he give of a cookie?
Mathematics
1 answer:
ivann1987 [24]3 years ago
6 0

Answer:

four

Step-by-step explanation:

I'm assuming each friend wants one whole cookies because it's not specified

4 friends/one cookie is four

I'm sorry if this wasn't what you wanted!

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HELPPP PLEASE 20 POINTS<br> What is the surface area of this design?
gizmo_the_mogwai [7]

Answer:

197

Step-by-step explanation:

You have 6 sides of this object. So we will calculate six surface areas.

P1=5x5=25 ( on the top)

P2=9x5=45 ( on the bottom)

P3= 5x5= 25 (left side)

P4=6,4x5=32 (rightside)

P5= (9+5)x5/2=70/2=35 ( front trapeze)

P6=P5=35 ( behided trapeze)

P= p1+p2+p3+p4+p5+p6=

25+45+25+32+35+35 =197

8 0
3 years ago
How to factor completely x2-10x+21
HACTEHA [7]
X2-10x+21
=(x-3)(x-7)
hope this helps!
5 0
3 years ago
PLZ HELP its only one problem and the instructions are on the screenshot
djyliett [7]

Answer:

Equal to!

Step-by-step explanation:

2 x 1.08 is 2.16

(1.08/100) x 200 = 2.16

2.16 = 2.16

3 0
3 years ago
What is the slope of the line that passes through the points (-4, -9) and (5, 3)
egoroff_w [7]

Answer:

4/3

Step-by-step explanation:

Moving from (-4, -9) to (5, 3), x (the 'run') increases by 9 from -4 to 5, and y (the 'rise') increases by 12 from -9 to +3.  Thus, the slope of the line connecting the two points is

m = rise / run = 12/9 = 4/3

It may help to think of the change in x (9) as the horizontal leg of a right triangle and the change in y (12) as the vertical leg.  Then  

m = (vertical leg length) / (horizontal leg length) = 12/9 = 4/3

5 0
3 years ago
PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!!<br><br> Which graph represents the function?
fiasKO [112]

Answer:  (C) <em>bottom left graph</em>

<u>Step-by-step explanation:</u>

Create a table for each interval:

\begin {array}{c|l}\underline{\ x\ }&\underline{(x+2)^2=y}\\ -3&(-3+2)^2=1\\-2&(-2+2)^2=0\\-1&(-1+2)^2=1\quad \text{ope n dot}}\\\end{array}\\\\\text{Note: All of the graphs satisfy these coordinates}\\\\\begin {array}{c|l}\underline{\ x\ }&\underline{(|x|+1=y}\\ -1&|-1|+1=2\quad \text{closed dot}}\\0&|0|+1=1\\1&|1|+1=2\quad \text{closed dot}}\\\end{array}\\\\\text{Note: Graph C is the only graph that satisfies these coordinates}

No need to create the table for the last interval.


3 0
3 years ago
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