<span>Ending Amt = Bgng Amt * e ^-0.03t
In this equation, the "-0.03" is the decay factor or "k"
We can now solve for half-life by this equation:
</span>t = <span>(<span>ln [y(t) ÷ a]<span>)<span> ÷ -k (we can say beginning amount = 200 and ending amount = 100
</span></span></span></span>t = <span>(<span>ln [200 ÷ 100]<span>)<span> ÷ -k
</span></span></span></span>t = <span>(<span>ln [2]<span>)<span> ÷ -k
</span></span></span></span>t = 0.69314718056<span> ÷ --.03
t =</span><span><span><span> 23.1049060187
</span>
about 23 years
</span></span>
it is between 1 and 3 but i would go for 3, if choose all that would choose 1,2,3
Answer:
86.7 gallons
Step-by-step explanation:
I literally went decimal by decimal to find it. So theres no way it's wrong
<em>Greetings from Brasil...</em>
According to the annex, we note that
1 qt = 1 quart = 0.95L
To solve this problem, just apply some rules of 3.....
1st - how many qt's are in 15.5 cups
qt cup
1 ---------- 4
X ---------- 15.5
4 · X = 1 · 15.5
4X = 15.5
X = 15.5 ÷ 4
X = 3.875qt
Last rule of 3 to know how many liters there are in 3.875qt:
qt litres
1 ---------- 0.95
3.875 ---------- Y
1 · Y = 0.95 · 3.875
<h2>Y = 3.68L</h2>
In a day a young man should drink 3.68L of water