Answer:
One solution.
Step-by-step explanation:
To determine the number of possible solutions for a triangle with A = 113° , a = 15, and b = 8, we're going to use the law of sines which states that: "<em>When we divide side a by the sine of angle A it is equal to side b divided by the sine of angle B, and also equal to side c divided by the sine of angle C</em>".
Using the law of sines we have:


Solving for B, we have:

∠B = 29.4°
Therefore, the measure of the third angle is: ∠C = 37.6°
There is another angle whose sine is 0.4909 which is 180° - 29.4° = 150.6 degrees. Given that the sum of all three angles of any triangle must be equal to 180 deg, we can't have a triangle with angle B=113° and C=150.6°, because B+C>180.
Therefore, there is one triangle that satisfies the conditions.
T(n)=t(0)xR to the n power since the sequence is geometric
t(0)=1.5 because 1.5x2=3
R=2
Four times d to the third minus ten
The volume of a cone is one-third of the product of the area of the base times the height, i.e.
(1/3)π(r^2)*h = (1/3)π(3cm)^2 *(8cm) = 75.40 cm^3
Now multiply that by the number of cones: 6 * 75.40 cm^3 = 452.40 cm^3.
Then the answer is 452 cm^3