W = L - 7
WL = 78
(L-7)L = 78
L^2 - 7L - 78 = 0
Factorize: (L-13)(L+6) = 0
L = 13 or -6
A length cannot be negative, so the length must be 13 miles.
The width is 13-7 = 6 miles.
Answer:
The length of the third side is ( x - 2 )
Step-by-step explanation:
Volume of a box is the product of its length, width and height.
Volume of box = length × width × height.
One side is (x - 4) and another side is (2x + 1).
These given sides can be either length, height or width.
The volume of a box is given by V = 2x3-11x2 +10x +8. This means each of the sides are factors of the volume. To get the third side, we divide the volume by the product of the two given sides.
Product of the two given sides =
( x-4 ) (2x + 1) = 2x^2 + x - 8x + 4
= 2x^2 - 7x - 4
The long division is shown on the attached photo
The length of the third side is ( x - 2 )
Answer:
-16/65
Step-by-step explanation:
Given sinα = 3/5 in quadrant 1;
Since sinα = opp/hyp
opp = 3
hyp = 5
adj^2 = hyp^2 - opp^2
adj^2 = 5^2 = 3^2
adj^2 = 25-9
adj^2 = 16
adj = 4
Since all the trig identity are positive in Quadrant 1, hence;
cosα = adj/hyp = 4/5
Similarly, if tanβ = 5/12 in Quadrant III,
According to trig identity
tan theta = opp/adj
opp = 5
adj = 12
hyp^2 = opp^2+adj^2
hyp^2 = 5^2+12^2
hyp^2 = 25+144
hyp^2 = 169
hyp = 13
Since only tan is positive in Quadrant III, then;
sinβ = -5/13
cosβ = -12/13
Get the required expression;
sin(α - β) = sinαcosβ - cosαsinβ
Substitute the given values
sin(α - β) = 3/5(-12/13) - 4/5(-5/13)
sin(α - β)= -36/65 + 20/65
sin(α - β) = -16/65
Hence the value of sin(α - β) is -16/65
Can you send a photo of it? I can't understand
