3 years ago

3(6p-1)=11p-45 heeelp

Mathematics

2 answers:

Leokris [45]3 years ago

8 0

Answer:

multiply 3 from 6p and -1

18p - 3 = 11p - 45

18p - 11p = -45 + 3

7p = - 42 cut 42 by 7 in 6 times 7x6= 42

p= -6 is answer... ❤️

aksik [14]3 years ago

4 0

Answer:

p = -6

Step-by-step explanation:

pls give brainliest if im right

You might be interested in

PREGUNTA 3PRODUCCION Y COSTOS DE UNA EMPRESA ………………. (04 PUNTOS)SEA q = f ( T / K ) .................... q = PRODUCTO TOTAL FISI

worty [1.4K]

Answer:

hi I am new here ☺ ✨ ☺ ✨ ☺ ✨ ☺

3 0

3 years ago

One fifth of one number and one fourth of a number are added, the result is 29. What is the original number?

Morgarella [4.7K]

Answer:

$\dfrac{580}{9}$

Step-by-step explanation:

$\dfrac{1}{5}x + \dfrac{1}{4}x = 29$

$\dfrac{4}{20}x + \dfrac{5}{20}x = 29$

$\dfrac{9}{20}x = 29$

$x = 29 \times \dfrac{20}{9}$

$x = \dfrac{580}{9}$

Answer: $\dfrac{580}{9}$

5 0

3 years ago

7. Using the distance formula, calculate how far Hector threw the ball. (4 points: 2

iragen [17]

The required distance covered is 90 units

<h3>Distance formula</h3>

The formula for calculating the distance between two points is expressed as shown:

$D=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

The required coordinates missing are (0, 42.78) and (90.42.78). Substiute the coordinate into the formula:

$D=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

$D=\sqrt{(42.78-42.78)^2+(90-0)^2}\\D=\sqrt{(0^2+(90)^2}\\D = 90 units$

Hence the required distance covered is 90 units

Learn more on distance formula here: brainly.com/question/1872885

7 0

2 years ago

Help urgent, which functions are bounded below but not above? Choose all answers that apply.

evablogger [386]

Answer:

c, e, f, and i

Step-by-step explanation:

a. is bounded above at y = 1 and below at y = 0

b. is unbounded both above and below

c. is bounded below at y = 0 and unbounded above

d. is unbounded both above and below

e. is bounded below at y = 0 and unbounded above

f. is bounded below at y = 0 and unbounded above

g. is bounded below at y = 0 and bounded above at y = 1

h. is unbounded both above and below

i. is bounded below at y = 0 and unbounded above

j. is unbounded both above and below

3 0

3 years ago

Colin ties 5 groups of balloons to the fence. There are 3 orange balloons

maxonik [38]

Answer:

ok? what is the question?

4 0

3 years ago

Read 2 more answers