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Kaylis [27]
3 years ago
9

For each of the following portions,draw a diagram of the mixture in the jar. Then shade a layer that would correspond this porti

ons from least to greatest
Mathematics
1 answer:
kakasveta [241]3 years ago
4 0
Hey um... I need a pic to answer this because I want to help u,really I do,but I can't help much cuz i'm in the 4th grade,and ur in middle jail/prision(school)

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Graph the system by hand.
weqwewe [10]

Answer:

dont khan academy

Step-by-step explanation:

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7 0
2 years ago
Calcula la altura de Juan sabiendo que proyecta una sombra de 2 metros en el momento en que Pedro que mide 1,80 metros proyecta
den301095 [7]

Answer:

La altura de Juan por lo tanto es de 1.6 metros de altura

Step-by-step explanation:

Segun los datos que se encuentran en el ejercicio, tenemos lo siguiente:

Juan proyecta una sombra de 2 metros en el momento en que Pedro que mide 1,80.

Supongamos que x es la altura de juan que tenemos que calcular.

La altura de Juan por lo tanto la podemos calcular de la siguiente manera con la siguiente formula:

x= (1.8 metros/2.25 metros)*2

x=1.6 metros

La altura de Juan por lo tanto es de 1.6 metros de altura

5 0
2 years ago
3/11 of the spectators at a basketball game are children. There are 800 more adults than children. How many people are at the ba
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6 0
3 years ago
A=4ℼR2 solve for R<br> SHOW ALL STEPSSSSSSSSSSSSS
GuDViN [60]

Given problem;

  A  = 4 π R²

  To solve for R, we have to make it the subject of the expression.

Since

      A  = 4 π R² , follow these steps to find R;

    Multiply both sides by \frac{1}{4\pi }  

 A x \frac{1}{4\pi }  =  \frac{1}{4\pi } x 4 π R²

          \frac{A}{4\pi }   = R²

Then find the square root of both sides

        √R²  = \sqrt{\frac{A}{4\pi } }  

            R  = \sqrt{\frac{A}{4\pi } }

The solution is \sqrt{\frac{A}{4\pi } }

3 0
3 years ago
GEOMETRY// Area? Also please provide an explanation(:
Zina [86]

Answer:

A = 80

Step-by-step explanation:

B = 8

H = 10

Area of a Parallelogram = B x H = 8 x 10 = 80

8 0
3 years ago
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