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2 years ago

Can someone plzz help me with this 86points

Mathematics

1 answer:

just olya [345]2 years ago

7 0

Answer:I would do the same thing which is copy and paste because its very

difficult to find out how to do it but ill keep trying

Step-by-step explanation:

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You are given that 4a-2b = 10 (a) Write down the value of 2a - b

Simora [160]

Answer:

2a - b = 5

Step-by-step explanation:

4a - 2b = 10

take out the highest common factor of the left side

2(2a - b) = 10

divide both sides by two

2a - b = 10/2

2a - b = 5

6 0

3 years ago

X^3 = 125 over 27 CAN I PLEASE GET HELP

Zinaida [17]

X³ = 125/27

Cube root both sides to isolate the variable:

∛x³ = ∛(125/27)

x = ∛(125/27)

∛125 = 5, ∛27 = 3

x = 5/3

5 0

3 years ago

A cylinder with a height of 12 cm has a volume of 1728 pi cm^ 3 What is the diameter of the cylinder?

blsea [12.9K]

Answer:

Step-by-step explanation:

let r be radius of the cylinder.

volume of cylinder=πr²h

1728π=πr²×12

r²=1728 π/12π=144

r=√144=12

diameter=2r=2×12=24 cm

3 0

2 years ago

Read 2 more answers

Solve each system of equations; nonlinear algebra 2 x2 + x + y - 26 = 0 x + y = 1

BigorU [14]

Answer:

(5,-4) and (-5,6)

Step-by-step explanation:

Given:

$\left\{\begin{array}{l}x^2+x+y-26=0\\ \\x+y=1\end{array}\right.$

Solve it. First, express y in terms of x from the second equation:

$y=1-x$

Substitute it into the first equation:

$x^2+x+1-x-26=0\\ \\x^2-25=0\\ \\(x-5)(x+5)=0$

Apply zero product property:

$x-5=0\ \text{or}\ x+5=0$

So,

$x=5\ \text{or}\ x=-5$

When $x=5,$ then $y=1-5=-4$

When $x=-5,$ then $y=1-(-5)=6$

We get two solutions: (5,-4) and (-5,6)

8 0

3 years ago

Alyssa took a math test for 20 questions and she answered 16 questions correctly in order to get an a she needs to answer at lea

Elenna [48]

Answer:

She did not qualify the exam.

Step-by-step explanation:

Given data

Total no of question in a test = 20

No. of question answered correctly = 16

Percentage of question answered correctly

$(\frac{16}{20}) 100 = 80$

But in order to get in the exam the student must have to score at least 90 %. But she got only 80 % so she did not qualify the exam.

6 0

2 years ago