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3 years ago

5

Urgant !! 3(2x-4) - 6(x-3) please provide explanation

2 answers:

arsen [322]3 years ago

6 0

3 (2x-4)-6 (x-3)
Distribute by multiplication 3 to both 2x and -4
And distribute by multiplication -6 to both x and -3

6x-12-6x+18
Add like terms

6

DIA [1.3K]3 years ago

3 0

3(2x - 4) - 6(x - 3)
Distribute the 3 and the -6
6x - 12 -6x + 18
Combining like terms the expression simplifies to 6

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Please help ASAP!!!!!!!

vladimir2022 [97]

Answer: c

Step-by-step explanation:

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3 years ago

The first term of a geometric sequence is 6 and the fourth term is 384. What is the sum of the first 10 terms of the correspondi

aleksandrvk [35]

Answer:

2097150

Step-by-step explanation:

<u>GIVEN :-</u>

First term of G.P. = 6
Forth term of G.P. = 384

<u>TO FIND :-</u>

Sum of first 10 terms of the G.P.

<u>CONCEPT TO BE USED IN THIS QUESTION :-</u>

<em>Geometric Progression :-</em>

It's a sequence in which the successive terms have same ratio.

General form of a G.P. ⇒ a , ar , ar² , ar³ , ....... [where a = first term ; r = common ratio between successive terms]

Sum of 'n' terms of a G.P. ⇒ $\frac{a(r^n - 1)}{r-1}$ .

<em>[NOTE :- </em> $\frac{a(1-r^n)}{1-r}$ can also be the<em> formula for "Sum of n terms of G.P." because if you put 'r' there (assuming r > 0) you'll get negative value in both the numerator & denominator from which the negative sign will get cancelled from the numerator & denominator. </em><em>YOU'LL BE GETTING THE SAME VALUE FROM BOTH THE FORMULAES.</em><em>]</em>

<u>SOLUTION :-</u>

Let the first term of the G.P. given in the question be 'a' and the common ratio between successive terms be 'r'.

⇒ a = 6

It's given that <u>forth term</u> is 384. So from "General form of G.P." , it can be stated that :-

$=> ar^3 = 384$

$=> 6r^3 = 384$

Divide both the sides by 6.

$=> \frac{6r^3}{6} = \frac{384}{6}$

$=> r^3 = 64$

$=> r = \sqrt[3]{64} = 4$

Sum of first 10 terms $= \frac{6(4^{10}-1)}{4 - 1}$

$= \frac{6(1048576 - 1)}{3}$

$= 2 \times 1048575$

$= 2097150$

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3 years ago

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scoundrel [369]

Answer:

6. C.

Step-by-step explanation:

Stating it bisects and B is the common angle.

8 0

4 years ago

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A batch of bottles were packed in 25 boxes with 12 bottles in each box. If the same batch is packed using 20 bottles in each box

Firlakuza [10]

hey ,

here is your answer,

_______________

Let the number of boxes filled, by using 20 bottles in each box, be x.

The following table is obtained.

______________________

| Number of bottles. 12. 20 |

| |

| Number of boxes 25. x. |

---------------------------------------------

More the number of bottles, lesser will be the number of boxes.

Hence, the number of bottles and the number of boxes required to pack these are inversely proportional to each other.

Therefore,

12 × 25 = 20× x

Hence, the number of boxes required to pack these bottles is 15.

3 0

3 years ago

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Lines e and f are parallel. The m9 = 80° and m5 = 55°. Which angle measures are correct? Check all that apply. m2 = 125° m3 = 55

Scorpion4ik [409]

I’ve answered this question before, so please see the attached image.

The solution would be like this for this specific problem:

1, 4, 5, 8 = 55<span>
2, 3 , 6, 7 = 125
9, 12, 13, 16 = 80
10, 11, 14 ,15 = 100</span>

<span>So, the angle measures that are correct are:

</span>

m12 = 100

m8 = 55

m14 = 100

<span>m16 = 80</span>

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3 years ago

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