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pychu [463]
3 years ago
13

The greatest common factor of 3m2n + 12mn2 is

Mathematics
2 answers:
Kamila [148]3 years ago
8 0
3m^2n+12mn^2
In both the sets, 3 and m as well as n can be found as common factors.
So,
3mn( m+4n)


Therefore the answer is 3mn (#3)
Elena L [17]3 years ago
6 0
3m²n + 12mn²
3mn(m) + 3mn(4n)
3mn(m + 4n)

The GCF of 3m²n + 12mn² is 3mn.
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Naddika [18.5K]

X=180-57-57=66

<em>Dababy sus</em>

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If you’re factoring it, it’s

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5 0
2 years ago
Choose 5 cards from a full deck of 52 cards with 13values (2, 3, 4, 5, 6, 7, 8, 9, 10, J, Q, K, A) and 4 kinds(spade, diamond, h
Delvig [45]

Answer:

a) 182 possible ways.

b) 5148 possible ways.

c) 1378 possible ways.

d) 2899 possible ways.

Step-by-step explanation:

The order in which the cards are chosen is not important, which means that we use the combinations formula to solve this question.

Combinations formula:

C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

In this question, we have that:

There are 52 total cards, of which:

13 are spades.

13 are diamonds.

13 are hearts.

13 are clubs.

(a)Two-pairs: Two pairs plus another card of a different value, for example:

2 pairs of 2 from sets os 13.

1 other card, from a set of 26(whichever two cards were not chosen above). So

T = 2C_{13,2} + C_{26,1} = 2*\frac{13!}{2!11!} + \frac{26!}{1!25!} = 182

So 182 possible ways.

(b)Flush: five cards of the same suit but different values, for example:

4 combinations of 5 from a set of 13(can be all spades, all diamonds, and hearts or all clubs). So

T = 4*C_{13,5} = 4*\frac{13!}{5!8!} = 5148

So 5148 possible ways.

(c)Full house: A three of a kind and a pair, for example:

4 combinations of 3 from a set of 13(three of a kind ,c an be all possible kinds).

3 combinations of 2 from a set of 13(the pair, cant be the kind chosen for the trio, so 3 combinations). So

T = 4*C_{13,3} + 3*C_{13.2} = 4*\frac{13!}{3!10!} + 3*\frac{13!}{2!11!} = 1378

So 1378 possible ways.

(d)Four of a kind: Four cards of the same value, for example:

4 combinations of 4 from a set of 13(four of a kind, can be all spades, all diamonds, and hearts or all clubs).

1 from the remaining 39(do not involve the kind chosen above). So

T = 4*C_{13,4} + C_{39,1} = 4*\frac{13!}{4!9!} + \frac{39!}{1!38!} = 2899

So 2899 possible ways.

4 0
3 years ago
What is the answer to y=2x-9
stiv31 [10]

Sorry to break it to you, but...

That's a line equation my dude. There's no answer.

5 0
3 years ago
Read 2 more answers
Plot the complex number 5i and find its absolute value
cupoosta [38]
Check the picture below.

\bf 5i\implies \stackrel{a}{0}~~\stackrel{b}{+5}i\implies \stackrel{\stackrel{absolute~value}{modulus}}{r=\sqrt{a^2+b^2}}\implies r=\sqrt{0^2+5^2}\implies r=5

4 0
3 years ago
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