Ask question

Ask question

All categories

4 years ago

7

Paul is creating a pizza with a choice of crust, one type of cheese, one meat, and one vegetable topping. If he can choose from

2 different types of crust, 3 types of cheese, 4 types of meat toppings, and 7 types of vegetable toppings, how many pizzas are possible

2 answers:

iren [92.7K]4 years ago

4 0

168 pizzas are possible

mixer [17]4 years ago

3 0

168 pizzas would be possible by doing 3x2x4x7.

You might be interested in

Which represents the solution(s) of the graphed system of equations, y = x2 + 2x – 3 and y = x – 1?

Sonja [21]

Answer:

Second option: (-2,-3) and (1,0)

Step-by-step explanation:

Given the system of equations $\left \{ {{y = x^2 + 2x-3} \atop {y = x - 1}} \right.$ , you can rewrite them in this form:

$x^2 + 2x-3= x - 1$

Simplify:

$x^2 + 2x-3-x+1=0\\\\x^2+x-2=0$

Factor the quadratic equation. Choose two number whose sum be 1 and whose product be -2. These are: 2 and -1, then:

$(x+2)(x-1)=0\\\\x_1=-2\\\\x_2=1$

Substitute each value of "x" into any of the original equation to find the values of "y":

$y_1= (-2) - 1=-3\\\\y_2=(1)-1=0$

Then, the solutions are:

(-2,-3) and (1,0)

7 0

3 years ago

Read 2 more answers

What is the value of x?<br> Please help fast will give brainliest help fast

serious [3.7K]

Answer:

17

Step-by-step explanation:

because of the kind of angle it is, the two equations are equal. So, put the equations equal to each other and solve:

x+35=3x+1

combine like terms (by subtracting)

2x=34

isolate x by dividing by 2

x=17

17

8 0

3 years ago

Read 2 more answers

Consider writing onto a computer disk and then sending it through a certifier that counts the number of missing pulses. Suppose

Furkat [3]

Answer:

a) 0.164 = 16.4% probability that a disk has exactly one missing pulse

b) 0.017 = 1.7% probability that a disk has at least two missing pulses

c) 0.671 = 67.1% probability that neither contains a missing pulse

Step-by-step explanation:

To solve this question, we need to understand the Poisson distribution and the binomial distribution(for item c).

Poisson distribution:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}
$

In which

x is the number of sucesses

$
e = 2.71828$ is the Euler number

$\mu$ is the mean in the given interval.

Binomial distribution:

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

Poisson mean:

$\mu = 0.2$

a. What is the probability that a disk has exactly one missing pulse?

One disk, so Poisson.

This is P(X = 1).

$P(X = 1) = \frac{e^{-0.2}*0.2^{1}}{(1)!} = 0.164
$

0.164 = 16.4% probability that a disk has exactly one missing pulse

b. What is the probability that a disk has at least two missing pulses?

$P(X \geq 2) = 1 - P(X < 2)$

In which

$P(X < 2) = P(X = 0) + P(X = 1)$

In which

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}
$

$P(X = 0) = \frac{e^{-0.2}*0.2^{0}}{(0)!} = 0.819$

$P(X = 1) = \frac{e^{-0.2}*0.2^{1}}{(1)!} = 0.164
$

$P(X < 2) = P(X = 0) + P(X = 1) = 0.819 + 0.164 = 0.983$

$P(X \geq 2) = 1 - P(X < 2) = 1 - 0.983 = 0.017$

0.017 = 1.7% probability that a disk has at least two missing pulses

c. If two disks are independently selected, what is the probability that neither contains a missing pulse?

Two disks, so binomial with n = 2.

A disk has a 0.819 probability of containing no missing pulse, and a 1 - 0.819 = 0.181 probability of containing a missing pulse, so $p = 0.181$

We want to find P(X = 0).

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{2,0}.(0.181)^{0}.(0.819)^{2} = 0.671$

0.671 = 67.1% probability that neither contains a missing pulse

8 0

3 years ago

Brand Number of Packets Cost

Sveta_85 [38]

Answer:

B) Brand 2

Step-by-step explanation:

Brand 1: $10.68 ÷ 12 = 0.89

Brand 2: $9.44 ÷ 16 = 0.59

Brand 3: $15.30 ÷ 18 = 0.85

Brand 4: $21.84 ÷ 24 = 0.91

Brand 5: $20.40 ÷ 30 = 0.68

Least cost per packet is of Brand 2

3 0

3 years ago

Read 2 more answers

<img src="https://tex.z-dn.net/?f=%20log_%7B10%7D%20%5C%3A%20x%3D%204" id="TexFormula1" title=" log_{10} \: x= 4" alt=" log_{10}

Alinara [238K]

Answer:

$log_{10}(x ) = 4$

the property of Logarithms,

$log_a(x)= y \\ \implies x=a^y$

so,

$x = {10}^{4}$

7 0

3 years ago