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3 years ago

Brand Number of Packets Cost

Mathematics

2 answers:

Sveta_85 [38]3 years ago

3 0

Answer:

B) Brand 2

Step-by-step explanation:

Brand 1: $10.68 ÷ 12 = 0.89

Brand 2: $9.44 ÷ 16 = 0.59

Brand 3: $15.30 ÷ 18 = 0.85

Brand 4: $21.84 ÷ 24 = 0.91

Brand 5: $20.40 ÷ 30 = 0.68

Least cost per packet is of Brand 2

Tcecarenko [31]3 years ago

3 0

Answer:

Brand 2 is cheapest per 1 single dip from the 12

We know its cheaper each packet as we divide by its number of dips to its total to find single dip prices.

Therefore, as example single dip for Brand 2 = $0.59

The others range from $0.59 to $0.91 making the single range $32 (the difference in values higher to lower) as a single dip cost.

Their mean is 392 / 5 = $0.78 as a single dip cost.

Step-by-step explanation:

Brand 1 12 10.68 = 0.89

Brand 2 16 9.44 =0.59

Brand 3 18 15.30 =0.85

Brand 4 24 21.84 = 0.91

Brand 5 30 20.40 = 0.68

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A construction company purchased some equipment costing $300,000. The value of the equipment depreciates

goldfiish [28.3K]

Answer:

$11.9\ years$

Step-by-step explanation:

we know that

The formula to calculate the depreciated value is equal to

$V=P(1-r)^{x}$

where

V is the depreciated value

P is the original value

r is the rate of depreciation in decimal

x is Number of Time Periods

in this problem we have

$P=\$300,000\\r=14\%=14/100=0.14\\V=\$50,000$

substitute the values and solve for x

$50,000=300,000(1-0.14)^{x}$

$(50,000/300,000)=(0.86)^{x}$

$(5/30)=(0.86)^{x}$

Apply log both sides

$log(5/30)=(x)log(0.86)$

$x=log(5/30)/log(0.86)$

$x=11.9\ years$

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3 years ago

Read 2 more answers

I need help on these question ASAP!!!! This is Urgent

GarryVolchara [31]

Part 1: The equation of the line is $y=2x+1$

Part 2: The equation of the line in slope intercept form is $y=-3x-1$

Explanation:

Part 1: It is given that the point A is $(1,3)$ and the line B is $y=2 x-2$

To determine the line passing through the point A and parallel to line B, let us first determine the slope and y-intercept.

From the equation of line B, the slope is $m=2$

Substituting the point $(1,3)$ and $m=2$ in slope intercept form $y=mx+b$ , we have,

$3=2(1)+b$

$3=2+b$

$1=b$

Thus, the y-intercept is $b=1$

Let us substitute the values $m=2$ and $b=1$ in the slope intercept form $y=mx+b$ , we get,

$y=2x+1$

Thus, the equation of the line passing though point A and parallel to line B is $y=2x+1$

Part 2: The given two coordinates are $(-1,2)$ and $(1,-4)$

To determine the equation of line in slope intercept form, first we shall find the slope and y-intercept.

From the graph, we can see that the line touches the y-axis at -1.

Hence, the y-intercept is $b=-1$

The formula for slope is $m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}$

Substituting the coordinates $(-1,2)$ and $(1,-4)$ , we have,

$m=\frac{-4-2}{1+1} =\frac{-6}{2} =-3$

Thus, the slope is $m=-3$

Substituting the values $b=-1$ and $m=-3$ in the slope intercept formula $y=mx+b$ , we get,

$y=-3x-1$

Thus, the equation of the line in slope intercept form is $y=-3x-1$

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Margarita [4]

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sasho [114]

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