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elena55 [62]
4 years ago
11

For which values of a does ???? a a − 4 a + 4 a ???? have an inverse matrix?

Mathematics
1 answer:
Aleks [24]4 years ago
6 0

Answer:

A =  \dfrac{1}{16}\begin{bmatrix}a &-(a-4) \\ -(a+4) & a\end{bmatrix}

Step-by-step explanation:

given,

Matrix =

A = \begin{bmatrix}a &a-4 \\ a+4 & a\end{bmatrix}

determinant of matrix

|A| = a×a - (a-4)(a+4)

|A| = a² - a² +16

|A| = 16

inverse of the matrix

to calculate inverse of two matrix interchange the term a₁₁ with a₂₂ and multiply the -ve with a₁₂ and a₂₁

the inverse is

A =  \dfrac{1}{16}\begin{bmatrix}a &-(a-4) \\ -(a+4) & a\end{bmatrix}

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A box contains 7 yellow, 5 blue, and 4 red balls. Three balls are drawn at random. Find the probability that:
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Answer:

a) 7/80 = 0.0875

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Step-by-step explanation:

There are a total of 16 balls.  3 are selected.  There are ₁₆C₃ possible combinations.

a) If all 3 balls are the same color, they are either all yellow OR all blue OR all red.

The number of ways of choosing 3 yellow balls from 7 is ₇C₃.

The number of ways of choosing 3 blue balls from 5 is ₅C₃.

The number of ways of choosing 3 red balls from 4 is ₄C₃.

The total probability is:

P = (₇C₃ + ₅C₃ + ₄C₃) / ₁₆C₃

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b) The number of ways of choosing 2 yellow balls from 7 is ₇C₂.

The number of ways of choosing 1 blue ball from 5 is ₅C₁.

The probability of both is:

P = ₇C₂ ₅C₁ / ₁₆C₃

P = 21 × 5 / 560

P = 105 / 560

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P = 0.1875

c) If all 3 balls are different colors, then there is exactly 1 yellow, 1 blue, and 1 red.

The number of ways of choosing 1 yellow ball from 7 is ₇C₁.

The number of ways of choosing 1 blue ball from 5 is ₅C₁.

The number of ways of choosing 1 red ball from 4 is ₄C₁.

The probability of all events is:

P = ₇C₁ ₅C₁ ₄C₁ / ₁₆C₃

P = 7 × 5 × 4 / 560

P = 140 / 560

P = 1 / 4

P = 0.2500

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3 years ago
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