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statuscvo [17]
3 years ago
7

Solve the system of equations. y=7x y=2x + 20 x=? y=?

Mathematics
1 answer:
alekssr [168]3 years ago
6 0
X=4, y=28. 7x=2x+20, so subtract 2x from both sides and you’ll get 5x=20. Divide both sides by 5 and you’ll get x=4. Substitute this into the other equations and they will both equal 28.
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Each week you drive 150 miles your car gets 25 miles to the gallon and gas prices are three dollars per gallon how much gas mone
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5 0
3 years ago
A family purchased tickets to a museum and spent a total of $38.00. The family purchased 4 tickets. There was $1.50 processing f
Mademuasel [1]

From my work, i got 4x+$1.50=48 I hope it helps you.

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7 0
3 years ago
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What are the coordinates of the point that is 3/5 of the way from A(-9, 3) to B(21,-2)?
ANTONII [103]

Answer:

Building and solving an equation, it is found that the coordinates are: (9,0).

We are given two points: A(-9,3) and B(21, -2).

We also want point C(x,y).

C is 3/5 of the way from A to B, thus:

This is used to find both the x-coordinate and the y-coordinate of C.

First, the x-coordinate, considering .

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Step-by-step explanation:

6 0
2 years ago
If 25% of the students in elementary algebra courses receive a grade of A, and there are 300 students enrolled in elementary alg
djyliett [7]

Answer:

Total number of students receiving A grade = 75

Step-by-step explanation:

Total number of students enrolled in elementary algebra this year =300

Percentage of students receiving a grade of A = 25%

To find number of students that will receive a grade of A.

Solution:

In order to find the number of students that will receive a grade of A, we will find the percentage students receiving A grade of the total number of the student.

Number of students receiving A grade = 25\%\ of\textrm{ Total number of students}

⇒ 25\%\ of\ 300

Writing 25% as fraction and multiplying.

⇒ \frac{25}{100}\times 300

⇒ \frac{7500}{100}

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6 0
3 years ago
PLEASE HELP ME! I really need help y'all...
ikadub [295]

just a quick clarification, tis usually -4.9 and that's a rounded number to reflect earth's gravity on an object in motion, but -5 is close enough :)

\bf ~~~~~~\textit{initial velocity in meters} \\\\ h(t) = -4.9t^2+v_ot+h_o \quad \begin{cases} v_o=\textit{initial velocity}\\ \qquad \textit{of the object}\\ h_o=\textit{initial height}\\ \qquad \textit{of the object}\\ h=\textit{object's height}\\ \qquad \textit{at "t" seconds} \end{cases} \\\\[-0.35em] \rule{34em}{0.25pt}

\bf h(x)=-5(\stackrel{\mathbb{F~O~I~L}}{x^2-8x+16})+180\implies h(x)=-5x^2+40x-80+180 \\\\[-0.35em] ~\dotfill\\\\ ~\hfill h(x)=-5x^2+\stackrel{\stackrel{v_o}{\downarrow }}{40} x+\stackrel{\stackrel{h_o}{\downarrow }}{\boxed{100}}~\hfill

8 0
4 years ago
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