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3 years ago

Pi = 3.14

Mathematics

1 answer:

mr Goodwill [35]3 years ago

8 0

Area of circle= 3.14r^2
r= 4
A= 50.27

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What is the mode of the data set?<br> (Please help)

Snowcat [4.5K]

Answer:

the number that occures the most is the answer

Step-by-step explanation:

7 0

3 years ago

I need help in #24 snd #25 can someone help me please I need them done by tomorrow

Ivahew [28]

Well to display the first part of the question, simply say f(N) or y = $12.50n + 100. This represents the total money in your bank account as per the question.

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3 years ago

P Is inversely proportional to Q.

cluponka [151]

The proportion is 100:32.
You can put this into a fraction 100/32 and conclude that P is 3.3 repeating times larger than Q.
When Q=80, P will be 3.3 times larger than 80.
The answer is P = 266.6 repeating or 266.67.

6 0

3 years ago

What is the solution to the following system of linear equations?

Lostsunrise [7]

<span> x − 2y = −1 => x = 2y -1

2x + y = −12
2(2y - 1) + y = -12
4y - 2 + y = -12
5y = -10
y = -2
x = 2</span>·(-2) - 1
x = -4 - 1
x = -5

Answer <span>D (-5,-2)</span>

8 0

4 years ago

A book is to be randomly chosen from the library. The probability that a randomly-chosen book is fiction is

Sveta_85 [38]

Using Venn probabilities, and supposing the incomplete probabilities, it is found that there is a 0.35 = 35% probability that a randomly-chosen book from the library is fiction or has a white cover.

<h3>What is a Venn probability?</h3>

In a Venn probability, two non-independent events are related with each other, as are their probabilities.

The first step to solve a problem using Venn probabilities is identifying the events. In this problem, they are:

Event A: Fiction.

Event B: White cover.

The "or probability" is given by:

$P(A \cup B) = P(A) + P(B) - P(A \cap B)$

In this problem:

The probability that a randomly-chosen book is fiction is 0.15, hence $P(A) = 0.15$ .

The probability that randomly-chosen book has a white cover is 0.3, hence $P(B) = 0.3$

The probability that a randomly-chosen book is fiction and has a white cover is 0.1, hence $P(A \cap B) = 0.1$

Then:

$P(A \cup B) = P(A) + P(B) - P(A \cap B)$

$P(A \cup B) = 0.15 + 0.3 - 0.1$

$P(A \cup B) = 0.35$

0.35 = 35% probability that a randomly-chosen book from the library is fiction or has a white cover.

You can learn more about Venn probabilities at brainly.com/question/25698611

5 0

3 years ago