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riadik2000 [5.3K]
4 years ago
5

Can someone pleaseeeeeehelp me

Mathematics
1 answer:
Effectus [21]4 years ago
7 0
the answer will be bbcuz
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How to calculate the percentage of the third year .i want extra detailed steps
nirvana33 [79]
Nobody wants to do these because, I don't know why.
8 0
3 years ago
Mark and raquel were playing a word game.Raquel played the word math on a game board on a space marked’’triple points’.If her wo
Reika [66]

Answer:

111 points

Step-by-step explanation:

First, thing I like to do is to convert word problems into an eqaution or write down the important information.  So, Math = 37 points and now the points are tripled because of where she placed the word.  Also, tripled is implying that her base score for the word is 3 times the original value.

So, 37*3

= 111 points.

5 0
3 years ago
Read 2 more answers
( 7x + 1/2) + ( 7x - 7 and 1/2) Simplify
pishuonlain [190]

Answer:

The answer will be 7(2x - 1)

Step-by-step explanation:

1) Convert 7 and 1/2 to improper fraction. Use this rule: a b/c = ac + b/c

7x +  \frac{1}{2}  + 7x -  \frac{7 \times 2 + 1}{2}

2) Simplify 7 × 2 to 14 .

7x +  \frac{1}{2}  + 7x  -  \frac{14 + 1}{2}

3) Simplify 14 + 1 to 15.

7x +  \frac{1}{2}  + 7x -  \frac{15}{2}

4) Collect like terms.

(7x + 7x) + ( \frac{1}{2}  -  \frac{15}{2} )

5) simplify.

14x - 7

6) Factor out the common term 7.

7(2x - 1)

Therefor, the answer is 7( 2x - 1 ).

7 0
3 years ago
Please help solve this with working out :)
Anastaziya [24]
I hope this can help u

3 0
3 years ago
How do I solve for x
Alchen [17]
Greetings!

To find the length of any side of a right triangle, you can use the Pythagorean Thereom. It states that the squares of two sides are equal to the square of the hypotenuse:
a^2+b^2=c^2

Input the information from the diagram into the formula: 
(x)^2+(x+7)^2=(13)^2

Expand each term:
(x)^2+(x+7)^2=(13)^2

x^2+((x+7)(x+7))=169

x^2+(x(x+7)+7(x+7))=169

x^2+x^2+7x+7x+49=169

Combine like terms:
2x^2+14x+49=169

Add -169 to both sides:
(2x^2+14x+49)+(-169)=(169)+(-169)

2x^2+14x-120=0

Factor out the Common Term (2):
2(x^2+7x-60)=0

Factor the Complex Trinomial:
2(x^2-5x+12x-60)=0

2(x(x-5)+12(x-5))=0

2(x-5)(x+12)=0

Set Factors to equal 0:
x-5=0

x=5

or

x+12=0

x=-12

However, since we are solving for the side length, the only possible answer is 5 (a shape can't have a side with a negative length.)

The Solution Is: 
\boxed{x=5}

I hope this helped!
-Benjamin

6 0
3 years ago
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