What is the relative maximum and minimum of the function?
1 answer:
Take the derivitive
f'(x)=3x^2+12x
find where it equals zero
it equal zero at x=0 and x=-4
find the y values
f(0)=-36
f(-4)=-4
the critical points are (0,-36) and (-4,-4)
make sign chart
evalutat f'(x) at x=-5 and x=-1 and x=1, and see their signs
f'(-5)=(+)
f'(-1)=(-)
f'(1)=(+)
see below attachment
max is where sign changes from (+) to (-)
min is where sign changes from (-) to (+)
so
max at (-4,-4)
min at (0,-36)
none of the options are correct, do you have te right problem?
f'(x)=3x^2+12x
find where it equals zero
it equal zero at x=0 and x=-4
find the y values
f(0)=-36
f(-4)=-4
the critical points are (0,-36) and (-4,-4)
make sign chart
evalutat f'(x) at x=-5 and x=-1 and x=1, and see their signs
f'(-5)=(+)
f'(-1)=(-)
f'(1)=(+)
see below attachment
max is where sign changes from (+) to (-)
min is where sign changes from (-) to (+)
so
max at (-4,-4)
min at (0,-36)
none of the options are correct, do you have te right problem?
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Answer: The correct option is (2) (a, b).
Step-by-step explanation: We are given to find the co-ordinates of the point 'P' for the rectangle shown in the figure without using any new variable.
Since we are dealing with a rectangle, so each of its angle is a right angle. Hence, each side of the given rectangle is perpendicular to its adjacent side.
Also, the distance of a point from a line is the length of the perpendicular drawn from the point to the line.
So, we can see from the attached figure below that
Point 'P is at a distance of 'b' units from X-axis and 'a' units from Y-axis.
The distance of a point 'P' from Y-axis is its x co-ordinate the distance of 'P' from X-axis is its y co-ordinate.
Therefore, the co-ordinates of the point P will be
(distance of P from Y-axis, distance of P from X-axis)
= (a, b).
Thus, the correct option is (2) (a, b).
