Answer:
a. 0.71
b. 0.9863
Step-by-step explanation:
a. From the histogram, the relative frequency of houses with a value less than 500,000 is 0.34 and 0.37
-#The probability can therefore be calculated as:
Hence, the probability of the house value being less than 500,000 is o.71
b.
-From the info provided, we calculate the mean=403 and the standard deviation is 278 The probability that the mean value of a sample of n=40 is less than 500000 can be calculated as below:
Hence, the probability that the mean value of 40 randomly selected houses is less than 500,000 is 0.9863
The Poisson distribution defines the probability of k discrete and independent events occurring in a given time interval.
If λ = the average number of event occurring within the given interval, then
For the given problem,
λ = 6.5, average number of tickets per day.
k = 6, the required number of tickets per day
The Poisson distribution is
The distribution is graphed as shown below.
Answer:
The mean is λ = 6.5 tickets per day, and it represents the expected number of tickets written per day.
The required value of k = 6 is less than the expected value, therefore the department's revenue target is met on an average basis.
The independent variable (the one they want) is the # of hours worked, since that determines the price.
All the other answers contain information not included in the problem
Answer: x^9+3x^8+7x^7
Step-by-step explanation:
the ^ mean the exponent
