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nignag [31]
2 years ago
9

100POINTS AND I"LL MARK BRAINLIEST

Mathematics
2 answers:
Neko [114]2 years ago
7 0
<h2>Answer:</h2>
  • For almonds:

<u>Cost of 2 pounds</u> = $21.98

So, Cost of 1 pounds = 21.98/2 = $10.99

  • For dried apricots:

<u>Cost of 3 pounds</u> = $26.25

So, Cost of 1 pounds = 26.25/3 = $8.75

<u>Difference in their cost</u> = $10.99 - $8.75 = $2.24.

<u>Cost of dried apricots is less expensive by $2.24 per pound</u>.

GenaCL600 [577]2 years ago
6 0

Answer:

  • Dried Apricots are $2.24 less expensive

Step-by-step explanation:

<u>Almonds:</u>

  • Cost of 2 pounds = $21.98
  • Cost of 1 pound = $21.98/2 = $10.99

<u>Dried Apricots:</u>

  • Cost of 3 pounds = $26.25
  • Cost of 1 pound = $26.25/3 = $8.75

<u>Dried Apricots cost less by:</u>

  • $10.99 - $8.75 = $2.24
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The number of motor vehicles registered in millions in the US has grown as follows:
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Answer:

a) Figure attached

b) r=\frac{n(\sum xy)-(\sum x)(\sum y)}{\sqrt{[n\sum x^2 -(\sum x)^2][n\sum y^2 -(\sum y)^2]}}  

For our case we have this:

n=10 \sum x = 75.819, \sum y = 43.5231, \sum xy = 330.0321, \sum x^2 =574.8598, \sum y^2 =192.8274  

r=\frac{10(330.0321)-(75.81948)(43.5231)}{\sqrt{[10(574.8598) -(75.819)^2][10(192.8274) -(43.5231)^2]}}=0.989  

So then the correlation coefficient would be r =0.989

Step-by-step explanation:

Previous concepts

The correlation coefficient is a "statistical measure that calculates the strength of the relationship between the relative movements of two variables". It's denoted by r and its always between -1 and 1.

Solution to the problem

Part a

Year (x): 1940, 1945 1950, 1955, 1960, 1965, 1970, 1975, 1980, 1985

Vehicles (Y): 32.4, 31.0, 49.2, 62.7, 73.9, 90.4, 108.4, 132.9, 155.8, 171.7

After apply natural log for the two variables and create the scatterplot in excel we got the following result on the figure attached.

Part b

And in order to calculate the correlation coefficient we can use this formula:  

r=\frac{n(\sum xy)-(\sum x)(\sum y)}{\sqrt{[n\sum x^2 -(\sum x)^2][n\sum y^2 -(\sum y)^2]}}  

For our case we have this:

n=10 \sum x = 75.819, \sum y = 43.5231, \sum xy = 330.0321, \sum x^2 =574.8598, \sum y^2 =192.8274  

r=\frac{10(330.0321)-(75.81948)(43.5231)}{\sqrt{[10(574.8598) -(75.81948)^2][10(192.8274) -(43.5231)^2]}}=0.989  

So then the correlation coefficient would be r =0.989

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