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Mariana [72]
3 years ago
6

A cafeteria sells entrees and additional items. An entree costs $4.75, and each additional item costs $1.25. A customer pays $9.

75 for one entree and some additional items. How many additional items were ordered?
Mathematics
2 answers:
Savatey [412]3 years ago
7 0
Answer: 4

----------------------------------------------------------------------------------------------
Information Given
----------------------------------------------------------------------------------------------
Entree = $4.75
Addition items = $1.25 each

----------------------------------------------------------------------------------------------
Define x
----------------------------------------------------------------------------------------------
Let the number of addition item be x

----------------------------------------------------------------------------------------------
Construct equation
----------------------------------------------------------------------------------------------
9.75 = 4.75 + 1.25x

----------------------------------------------------------------------------------------------
Find x
----------------------------------------------------------------------------------------------
9.75 = 4.75 + 1.25x

----------------------------------------------------------------------------------------------
Subtract 4.75 from both sides
----------------------------------------------------------------------------------------------
5 = 1.25x

----------------------------------------------------------------------------------------------
Divide by 1.25 on both sides
----------------------------------------------------------------------------------------------
4 = x

----------------------------------------------------------------------------------------------
Answer: The customer ordered  4 additional items
----------------------------------------------------------------------------------------------
umka2103 [35]3 years ago
6 0
Hello!

ANSWER:

4 additional items were ordered.

EXPLANATION:

First, subtract the cost of the entree:

9.75 - 4.75 = 5

This means that the customer spent $5.00 on on additional items.
Each additional item costs $1.25. Divide:

5 ÷ 1.25 = 4

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T(x)=70(.80)*+20 where x is the time in minutes and the T is the temperature in degree celsius . What is the initial temperature
Serggg [28]

Answer:

The initial temperature of the coffee was 90°C.

Step-by-step explanation:

The function representing the temperature of the coffee after <em>x</em> minutes is:

T(x)=70\cdot(0.80)^{x}+20

T is the temperature in degree Celsius.

The initial temperature of the coffee will be at <em>x</em> = 0.

Compute the value of T (x) at x = 0 as follows:

T(x)=70\cdot(0.80)^{x}+20

T(0)=70\cdot (0.80)^{0}+20

        =70\times 1+20\\=70+20\\=90

Thus, the initial temperature of the coffee was 90°C.

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How to I solve this equation?
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x = \frac{45}{13}

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Find the sum S below:
goldfiish [28.3K]

Answer:

\rm\displaystyle \sum _{n = 1} ^{ \infty }  \frac{2}{(2n -1 )(2n + 1)}  \approx   \boxed{\frac{1}{2}}

Step-by-step explanation:

we want to figure out the <em>Sum</em> of the following infinite series:

\rm\displaystyle S = \frac{2}{1 \cdot 3} + \frac{2}{3 \cdot 5} + \frac{2}{5 \cdot 7} + ... + \frac{2}{(2n - 1)(2n + 1)}

we're given the nth term of the series so the infinite sum would be

\displaystyle \sum _{n = 1} ^{ \infty }  \frac{2}{(2n -1 )(2n + 1)}

to simplify the sum it, we need our calculas skills. recall that,

\displaystyle \sum _{i = 1} ^{ \infty }   a_{i} =  \lim _{x \to  \infty }\sum _{i = 1} ^{ n }   a_{i}

Thus,

\displaystyle \sum _{n = 1} ^{ \infty }  \frac{2}{(2n -1 )(2n + 1)}  =  \lim _{x \to \infty } \sum _{n = 1} ^{ k}  \frac{2}{(2n -1 )(2n + 1)}

<u>computing</u><u> the</u><u> </u><u>limit</u><u>:</u>

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simplify denominator:

\displaystyle   \lim _{n \to \infty }   \frac{ {2n}^{2} }{ { 4n}^{2}  - 1}

factor out n²:

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reduce fraction:

\displaystyle   \lim _{n \to \infty }   \frac{ 2 }{    4  -  \dfrac{1}{ {n}^{2}} }

as n approaches to infinity 1/n² approaches to 0 therefore:

\displaystyle   \frac{ 2 }{    4   }

reduce fraction:

\displaystyle    \frac{1}{2}

hence,

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