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Kitty [74]
4 years ago
15

If a certain number is multiplied by five, the result is the same as twenty-one plus twice the original number. What is the valu

e of the original number?
Mathematics
2 answers:
expeople1 [14]4 years ago
6 0
7
7 times 5 = 35
21 + 14 (7*2) = 35
Zepler [3.9K]4 years ago
4 0
Let the number be x

a.t.g.c
            5x = 21+ 2x
            5x-2x = 21
            3x    =   21
             
             x    =   21/3
    
             x    =   7      give me brainliest
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What is the domain and range of each curve?
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Answer:

Because the domain refers to the set of possible input values, the domain of a graph consists of all the input values shown on the x-axis. The range is the set of possible output values, which are shown on the y-axis.

Step-by-step explanation:

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4 years ago
two mountain bikers leave from the same parking lot and head in opposite directions on two different trails. the first rider goe
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Applying the required <em>rule </em>or <em>theorem</em>, it can be concluded that the second biker is <u>farther</u> from the <em>parking lot</em>. The distance of the bikers to the <em>parking lot</em> are:

i. First biker = 17.0 km

ii. Second biker = 20.22 km

The <u>path</u> of travel of both bikers would form a triangle. Applying the <u>Pythagoras</u> theorem to the path of the <em>first</em> biker would give his <u>distance</u> from the starting point. While applying the <u>cosine</u> rule to the path of <em>second</em> rider would gives his <u>distance</u> to the starting point.

Thus,

a. <u>To determine the distance of the first biker from the parking lot.</u>

Let the required <em>distance </em>be represented by x. Applying the Pythagoras theorem, we have:

hyp^{2} = adj 1^{2} + adj 2^{2}

x^{2} = 8^{2} + 15^{2}

   = 64 + 225

   = 289

x = \sqrt{289}

  = 17

x = 17 km

Thus, the <u>first</u> biker is 17.0 km from the <em>starting</em> point.

b. <u>To determine the distance of the second biker from the parking lot.</u>

Let the required <em>distance</em> be represented by x. So that applying the cosine rule, we have:

c^{2} = a^{2} + b^{2} - 2ab Cos θ

x^{2} = 8^{2} + 15^{2} - 2(15*8) Cos (180 - 20)

    = 64 + 225 - 240 Cos 160

    = 289 - 240 * -0.5

x^{2} = 289 + 120

   = 409

x = \sqrt{409}

 = 20.2237

x = 20.22 km

Thus, the <u>second</u> biker is 20.22 km from the <em>starting</em> point.

Therefore, the second biker is <u>farther</u> from the <em>parking lot</em>.

A sketch of the path of travel for the two bikers is attached for more clarifications.

Visit: brainly.com/question/22699651

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