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3 years ago

0.5 divided in to 4.5

Mathematics

2 answers:

Wewaii [24]3 years ago

6 0

The answer is 9 (nine)

Wittaler [7]3 years ago

4 0

Answer:

it be nine argrgrgrg now fillllllller

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Need help :(( plss help i took a screenshot so you can see

Mashcka [7]

Answer: 5:4

Step-by-step explanation: you divide them i believe :)

7 0

3 years ago

Read 2 more answers

I will give Brainliest to First and Correct Answer. Can Somebody please help...I really need help and I am struggling.

igor_vitrenko [27]

Answer: B' (5,8), C' (3,1)

Step-by-step explanation:

You can use the points A' (-1,8) and A (-2,-3) to find how many units point A was translated.

-2 + 1 = -1

-3 + 11 = 8

Then, you simply add 1 to the x-values of points B and C and 11 to the y-values of points B and C to get B' (5,8), C' (3,1).

I hope this helps!

4 0

2 years ago

James used a calculator to evaluate 8.931×7.38 but forgot to enter the decimal points. The answer he got was 6 591 078. What sho

likoan [24]

Answer:

65.91078

Step-by-step explanation:

You add the two decimals, that gives you two decimals. Use those two decimals and place them to the right of the answer. =0)

3 0

2 years ago

Felicity the unicorn is in the forest. She is enjoying a delicious melon. A weasel grabs the melon out of her mouth and starts t

kumpel [21]

Answer:

Step-by-step explanation:

bc i know

8 0

3 years ago

Write the equation of a polynomial of degree 3, with zeros 1, 2 and -1 where f(0)=2

drek231 [11]

Answer:

The equation of a polynomial of degree 3, with zeros 1, 2 and -1 is $x^{3}-2 x^{2}-x+2=0$

Solution:

Given, the polynomial has degree 3 and roots as 1, 2, and -1. And f(0) = 2.

We have to find the equation of the above polynomial.

We know that, general equation of 3rd degree polynomial is

$F(x)=x^{3}-(a+b+c) x^{2}+(a b+b c+a c) x-a b c=0$

where a, b, c are roots of the polynomial.

Here in our problem, a = 1, b = 2, c = -1.

Substitute the above values in f(x)

$F(x)=x^{3}-(1+2+(-1)) x^{2}+(1 \times 2+2(-1)+1(-1)) x-1 \times 2 \times(-1)=0$

$\begin{array}{l}{\rightarrow x^{3}-(3-1) x^{2}+(2-2-1) x-(-2)=0} \\ {\rightarrow x^{3}-(2) x^{2}+(-1) x-(-2)=0} \\ {\rightarrow x^{3}-2 x^{2}-x+2=0}\end{array}$

So, the equation is $x^{3}-2 x^{2}-x+2=0$

Let us put x = 0 in f(x) to check whether our answer is correct or not.

$\mathrm{F}(0) \rightarrow 0^{3}-2(0)^{2}-0+2=2$

Hence, the equation of the polynomial is $x^{3}-2 x^{2}-x+2=0$

3 0

3 years ago