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Thepotemich [5.8K]
3 years ago
5

0.5 divided in to 4.5

Mathematics
2 answers:
Wewaii [24]3 years ago
6 0
The answer is 9 (nine)
Wittaler [7]3 years ago
4 0

Answer:

it be nine argrgrgrg now fillllllller

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How to find the scale factor of something
AysviL [449]

Answer:

To find the scale factor, locate two corresponding sides, one on each figure. Write the ratio of one length to the other to find the scale factor from one figure to the other. In this example, the scale factor from the blue figure to the red figure is 1.6 : 3.2, or 1 : 2.

Step-by-step explanation:

5 0
3 years ago
(08.07 HC)
andreev551 [17]

Answer:

\textsf{A)} \quad x=-2, \:\:x=\dfrac{5}{2}

\textsf{B)} \quad \left(\dfrac{1}{4},-\dfrac{81}{8}\right)=(0.25,-10.125)

C)  See attachment.

Step-by-step explanation:

Given function:

f(x)=2x^2-x-10

<h3><u>Part A</u></h3>

To factor a <u>quadratic</u> in the form  ax^2+bx+c<em> , </em>find two numbers that multiply to ac and sum to b :

\implies ac=2 \cdot -10=-20

\implies b=-1

Therefore, the two numbers are -5 and 4.

Rewrite b as the sum of these two numbers:

\implies f(x)=2x^2-5x+4x-10

Factor the first two terms and the last two terms separately:

\implies f(x)=x(2x-5)+2(2x-5)

Factor out the common term  (2x - 5):

\implies f(x)=(x+2)(2x-5)

The x-intercepts are when the curve crosses the x-axis, so when y = 0:

\implies (x+2)(2x-5)=0

Therefore:

\implies (x+2)=0 \implies x=-2

\implies (2x-5)=0 \implies x=\dfrac{5}{2}

So the x-intercepts are:

x=-2, \:\:x=\dfrac{5}{2}

<h3><u>Part B</u></h3>

The x-value of the vertex is:

\implies x=\dfrac{-b}{2a}

Therefore, the x-value of the vertex of the given function is:

\implies x=\dfrac{-(-1)}{2(2)}=\dfrac{1}{4}

To find the y-value of the vertex, substitute the found value of x into the function:

\implies f\left(\dfrac{1}{4}\right)=2\left(\dfrac{1}{4}\right)^2-\left(\dfrac{1}{4}\right)-10=-\dfrac{81}{8}

Therefore, the vertex of the function is:

\left(\dfrac{1}{4},-\dfrac{81}{8}\right)=(0.25,-10.125)

<h3><u>Part C</u></h3>

Plot the x-intercepts found in Part A.

Plot the vertex found in Part B.

As the <u>leading coefficient</u> of the function is positive, the parabola will open upwards.  This is confirmed as the vertex is a minimum point.

The axis of symmetry is the <u>x-value</u> of the <u>vertex</u>.  Draw a line at x = ¹/₄ and use this to ensure the drawing of the parabola is <u>symmetrical</u>.

Draw a upwards opening parabola that has a minimum point at the vertex and that passes through the x-intercepts (see attachment).

5 0
2 years ago
Please Help! 30 points! Real answers pls The box plot below shows the total amount of time, in minutes, the students of a class
padilas [110]

Hii!

So I did this and I have A!

A: You cannot get the mean from the graph but you CAN get the third quartile!

B: To find the interquartile range (IQR) we subtract the third and first quartiles:

60-35 = 25

C:  An outlier would be much larger than the rest of the data or much smaller than the rest of the data. An outlier would make the "whisker" portion longer and could potentially slightly shift the box.

6 0
3 years ago
Read 2 more answers
A portion of a hiking trail slopes downward at about an 84° angle. To the
tangare [24]

C because if you divide the angle minus the feet you get 120

8 0
3 years ago
Read 2 more answers
The perimeter of a rectangle is 24. If the length is 5 times the width, what is the area?
KATRIN_1 [288]

Answer: Area is 20

Step-by-step explanation:

Perimeter of a rectangle is 24

Let the length be x

Let the breadth be Y

Length is 5times the breadth

I.e

X=5y

Formula for perimeter of a rectangle is

2(length + breadth)

= 2(x+y)

Substitute for x=5y

2(5y+y)=24

2(6y)=24

6y=24/2

6y=12

Y=12/6

Y=2

Breadth = 2

Since length =5y

Length=5(2)

Length = 10

Area of a rectangle = length × breadth

Area= 10×2

Area = 20

Area of the rectangle is 20

6 0
3 years ago
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