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wariber [46]
3 years ago
9

A. Y = 1/3(3)^x B. Y= 3(1/3)^x C. Y= (1/2)^x +2 D. Y=(2)^x - 1

Mathematics
1 answer:
Dimas [21]3 years ago
3 0

Answer:

B

Step-by-step explanation:

Look at the graph, it passes to (0,3), so you need to replace that coordinate into A,B,C,D. Then you can see, there is only B and C satisfies.

Y=3(\frac{1}{3} )^{0}=3.1=3.

and

Y=(\frac{1}{2} )^{0}+2=1+2=3

Next step, you can see when x approach to infinite then Y approach to 0.

Hence, we will take limit of B and C, if limit B or C equals to 0 then we will choose.

\lim_{x \to \infty} {3(\frac{1}{3})^x=3. \lim_{x \to \infty} {(\frac{1}{3})^x=3.0=0

and

\lim_{x \to \infty} {[(\frac{1}{2})^x+2]}=  \lim_{x \to \infty} {(\frac{1}{2})^x}+ \lim_{x \to \infty} {2}=0+2=2

We can see that only B is satisfied.

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