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3 years ago

If six is placed at the end of a two digit number the result is 294 greater than the number, what was the number?

1 answer:

6 0

If 6 is placed at the right end of AB, so the number is AB6.
the value of the three-digit number formed is 294 more than AB, means that if AB6 - 294 = AB 

AB 6
- 2 9 4
AB 

6 - 4 = B = 2 

If B = 2, then the tens digit is 2 - 9 (which can't be) so 12 - 9 = 3 = A 

A = 3, and B = 2 

check: 326 - 294 = 32

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what is the equation in point-slope form of the line passing through (0, 5) and (−2, 11)? (1 point) y − 5

makkiz [27]

According to the question, the line is through the points $(0,5)$ and $(-2,11)$

To calculate the slope using standard formula that is :

$m = \frac{(y(2)-y(1))}{(x(2)-x(1))} = \frac{(11-5)}{(-2-0)} =\frac{6}{-2} = -3$

Now the slope equation will be: $m(x(2)-x(1)) = (y(2)-y(1))$

$y-5 =(-3)(x-0) = y = -3(x)+5$

The slope-intercept form is: $y = -3x+5$

What is the equation of the line?

To represent the set of points in an algebraic form is known as the equation of line. The set of points represent lines in the coordinate system. The parameters can be calculated and those parameters are slope and y-intercept.

To learn more about the equation of the line from the given link:

brainly.com/question/14037984

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5 0

1 year ago

Y= -x +3 and y = x - 1

inysia [295]

Answer:

x=2 and y=1

Step-by-step explanation:

Rewrite equations:

y=−x+3;y=x−1

Step: Solve

y=−x+3

Step: Substitute−x+3foryiny=x−1:

y=x−1

−x+3=x−1

−x+3+−x=x−1+−x(Add -x to both sides)

−2x+3=−1

−2x+3+−3=−1+−3(Add -3 to both sides)

−2x=−4−2x−2=−4−2

(Divide both sides by -2)

x=2

Step: Substitute2forxiny=−x+3:

y=−x+3

y=−2+3

y=1(Simplify both sides of the equation)

Hope this Helps you :)

3 0

3 years ago

Please help me on this work please !

belka [17]

The second one I beileve is the answer to your question

5 0

3 years ago

Please help help help

lorasvet [3.4K]

Answer:

6x9+6+9 = 69

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

1) Use the rules of exponents to evaluate or simplify. Write without negative exponents.

AlladinOne [14]

$1)\\ 3*4^0=3*1=3\\\\ 2)\\ a^{-b=(\frac{1}{a})^b}}\\
\frac{1}{4^{-2}}=\frac{1}{(\frac{1}{4})^2}=\frac{1}{\frac{1}{16}}=1*\frac{16}{1}=16$

6 0

3 years ago