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nignag [31]
3 years ago
7

Hello please help i’ll give brainliest

Mathematics
1 answer:
inn [45]3 years ago
3 0
All of them baes (brainliest)
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I’m so confused pls help...
Mazyrski [523]

Answer:

D) 24

<u>Steps:</u>

(2/10)=3/(x-9)

》1/5=3/(x-9)

》(x-9)=15

》x = 15+9

》x = 24

7 0
3 years ago
Suppose all the counting numbers are arranged in columns as shown at the right. Under what letter will the number 1000 appear?
pentagon [3]
Letter D because you need to multiply all the letters of the alfabet (36) and multiply 36 by 1000 and then divide the answer by 100 and you get the letter D
4 0
3 years ago
A patio is a rectangle 12 feet wide and 16 feet long. The patio is completely surrounded by a fence. How long is the fence?
poizon [28]

12+12+16+16 = 56

the fence is 56 feet long

6 0
3 years ago
In a 30-60-90 triangle, if the the side opposite 30 degrees has a length
son4ous [18]

Might Want to draw this and Its very long but Hope it helped :)

Answer:

The sides are all of the same length - let's say a. The angles are all the same too, and since the angles must add up to 180∘, we conclude that the three angles in the equilateral triangle are equal to 180∘/3=60∘.

Now we do something sneaky. We draw a line all the way down from the top vertex of the triangle to the midpoint of the bottom line.

This new line cuts our equilateral triangle in half. What are the angles in one half?

The angle at the bottom is 90∘.

One of the angles is the same as one of the angles in the original equilateral triangle, so it is 60∘.

So the third angle must be 180∘−90∘−60∘=30∘.

Now the hypotenuse of this new triangle is a, the side length of the equilateral triangle. And the length of the shortest side is a/2, since the line we drew cut the bottom line in half.

8 0
3 years ago
PLEASEE HELP ANYONE WHO IS GOOD AT MATH
Lorico [155]
\sqrt{\frac{126xy^{5}}{32x^{3}}}=\sqrt{\frac{63y^{5}}{ax^{b}}}\\\\\sqrt{\frac{63y^{5}}{16x^{2}}}=\sqrt{\frac{63y^{5}}{ax^{b}}}\\\\\frac{\sqrt{63y^{5}}}{\sqrt{16x^{2}}}=\frac{\sqrt{63y^{5}}}{\sqrt{ax^{b}}}\\\\\frac{\sqrt{63y^{5}}}{\sqrt{16x^{2}}}*\frac{1}{\sqrt{63y^{5}}}=\frac{\sqrt{63y^{5}}}{\sqrt{ax^{b}}}*\frac{1}{\sqrt{63y^{5}}}\\\\\frac{1}{\sqrt{16x^{2}}}=\frac{1}{\sqrt{ax^{b}}}\\\\\sqrt{16x^{2}}=\sqrt{ax^{b}}

Thus for the two equations to be equal, a = 16 and b = 2.
8 0
3 years ago
Read 2 more answers
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