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vazorg [7]
3 years ago
6

X^4y - x^5y^4. Tell me the answer pls im late on assignments

Mathematics
1 answer:
Gnesinka [82]3 years ago
5 0
Pretty sure it’s X^4y x (1 - XY^3) Btw, lowercase x means multiply. Hope this helps!
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If ƒ (x ) = 2x 2 + 3, find ƒ (3).
dimulka [17.4K]

Answer:

f(x) = 2 \times 2 + 3 \\ f(3) = 4  + 3 \\ 3f = 7 \\ f =  \frac{7}{3}

<h2>Hope it help you</h2>
3 0
3 years ago
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It takes $8$ cups of chocolate chips to make $12$ cookies. How many cups of chocolate chips will it take to make $15$ cookies? P
Yuri [45]

Hello!!!

Answer:

11 cups of chocolate chips

Step-by-step explanation:

If we use the information we got from the problem we can see that 8 gives us 12. So all we need to do is add more to the orignal number(8) unitll we get 15. So 11 cups gives us 15 cookies.

Have a nice day!!!

4 0
3 years ago
What is the sum of /-10/ and /6/
kap26 [50]

Answer:

16

Step-by-step explanation:

-10 opposite is 10 which this \ or | means the its positive number. So 10 +6 is 16

7 0
3 years ago
34​% of college students say they use credit cards because of the rewards program. You randomly select 10 college students and a
finlep [7]

Answer:

a) There is a 18.73% probability that exactly two students use credit cards because of the rewards program.

b) There is a 71.62% probability that more than two students use credit cards because of the rewards program.

c) There is a 82% probability that between two and five students, inclusive, use credit cards because of the rewards program.

Step-by-step explanation:

There are only two possible outcomes. Either the student use credit cards because of the rewards program, or they use for other reason. So, we can solve this problem by the binomial distribution.

Binomial probability

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}

In which C_{n,x} is the number of different combinatios of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And \pi is the probability of X happening.

In this problem, we have that:

10 student are sampled, so n = 10

34% of college students say they use credit cards because of the rewards program, so \pi = 0.34

(a) exactly​ two

This is P(X = 2).

P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}

P(X = 2) = C_{10,2}.(0.34)^{2}.(0.66)^{8} = 0.1873

There is a 18.73% probability that exactly two students use credit cards because of the rewards program.

(b) more than​ two

This is P(X > 2).

Either a value is larger than two, or it is smaller of equal. The sum of the decimal probabilities must be 1. So:

P(X \leq 2) + P(X > 2) = 1

P(X > 2) = 1 - P(X \leq 2)

In which

P(X \leq 2) = P(X = 0) + P(X = 1) + P(X = 2)

So

P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}

P(X = 0) = C_{10,0}.(0.34)^{0}.(0.66)^{10} = 0.0157

P(X = 1) = C_{10,1}.(0.34)^{1}.(0.66)^{9} = 0.0808

P(X = 2) = C_{10,2}.(0.34)^{2}.(0.66)^{8} = 0.1873

P(X \leq 2) = P(X = 0) + P(X = 1) + P(X = 2) = 0.0157 + 0.0808 + 0.1873 = 0.2838

P(X > 2) = 1 - P(X \leq 2) = 1 - 0.2838 = 0.7162

There is a 71.62% probability that more than two students use credit cards because of the rewards program.

(c) between two and five inclusive

This is:

P = P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5)

P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}

P(X = 2) = C_{10,2}.(0.34)^{2}.(0.66)^{8} = 0.1873

P(X = 3) = C_{10,3}.(0.34)^{3}.(0.66)^{7} = 0.2573

P(X = 4) = C_{10,4}.(0.34)^{4}.(0.66)^{6} = 0.2320

P(X = 5) = C_{10,5}.(0.34)^{5}.(0.66)^{5} = 0.1434

P = P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5) = 0.1873 + 0.2573 + 0.2320 + 0.1434 = 0.82

There is a 82% probability that between two and five students, inclusive, use credit cards because of the rewards program.

6 0
3 years ago
If quadrilateral ABCD is a parallelogram, what are the correct values for x and y? x = 30, y = 3 x = 30, y = 2 x = 70, y = 2 x =
jeka57 [31]

Answer:

-70 is the correct answer

Step-by-step explanation:

To add fractions, find the LCD and then combine

4 0
3 years ago
Read 2 more answers
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