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mars1129 [50]
3 years ago
7

I’ve been at this for 3 hours. Please help.

Mathematics
1 answer:
Vladimir [108]3 years ago
7 0

Please help me! Answer my latest question

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What is the maximum height of the basketball when the player passes the ball to someone? Initially, the ball moves at a speed of
ZanzabumX [31]

Answer with explanation:

Since the motion of the ball is projectile motion we shall use the equations for projectile motion.

The maximum height achieved by the projectile is given by

h_{max}=\frac{v_{o}^{2}sin^{2}(\theta )}{2g}

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h_{max}=\frac{12^{2}\times sin^{2}(45)}{2\times 9.81}\\\\h_{max}=3.669m

The range of the projectile is given by

R=\frac{v_{o}^{2}sin(2\theta )}{2g}

Applying values we get

R=\frac{12^{2}\times sin(2\times 45 )}{2\times 9.81}\\\\R=7.339m

thus the maximum horizontal distance reached by the ball equals 7.339 meters after which it bounces thus a person standing 8 meters away will not be able to catch it.

(The height of the players is not taken into account since no info is given about their height.)

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3 years ago
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The best answer out of all of that is W if I’m right
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nikklg [1K]

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80

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2 years ago
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