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Vinvika [58]
3 years ago
12

Math 7.

Mathematics
2 answers:
White raven [17]3 years ago
5 0
<span>(-9x - 5) + (-3x - 3) =
combine the x terms, then the constants:
</span><span>-9x - 5 -3x - 3 =
-12x - 8</span>
IgorC [24]3 years ago
3 0
I think the answer is 54 because negative times a  negative number equals positive and 9x5 is 45 + another negative times negative so 3x3 is 9 so add 45+9 which is 54.
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The compound probability of two events, E and F, is ; the probability of E is and of F is . In two or more complete sentences, e
lorasvet [3.4K]

Answer:

Events E and F are not independent if the probability of event E occurring is affecting the probability of event F occurring.

Step-by-step explanation:

Two events are independent when the probability of one event occurring has no connection with that of the other event.

Example, when you toss a coin and roll a six sided die, the probability of getting a head or a tail has no connection with the probability of getting any number face.A real life example will be the probability going to the mall and owning a cat at home.These two have no influence on one another.

Mathematically independent events can be calculated as;

P(E∩F)=P(E)-P(F)

3 0
3 years ago
Members of the Video Digital club produce short videos. At the end
allsm [11]

Answer:

hggggggggjrhg

Step-by-step explanation:

fhhhhhhhgtrhrehr this is the right answer

5 0
3 years ago
Write the number 908,109 in expanded form
butalik [34]

(900,000)+(0)+(8,000)+(100)+(0)+(9)


Glad I could help u just need to write the zeros on which the number is in like 9 was in the hundred thousand place and hundred thousand has 6 zeros so we put the nine and add the 6 zeros. Have A Good day

6 0
3 years ago
On a particular production line, the likelihood that a light bulb is defective is 10%. seven light bulbs are randomly selected.
amid [387]

Answer:

0.9995

Step-by-step explanation:

10% = 0.10

1 - 0.10 = 0.9

n = number of light bulbs = 7

we calculate this using binomial distribution.

p(x) = nCx × p^x(1-p)^n-x

our question says at most 4 is defective

= (7C0 × 0.1⁰ × 0.9⁷) + (7C1 × 0.1¹ × 0.9⁶) + (7C2 × 0.1² × 0.9⁵) + (7C3 × 0.1³ × 0.9⁴) + (7C4 × 0.1⁴ × 0.9³)

= 0.478 + 0.372 + 0.1239 + 0.023 + 0.0026

= 0.9995

we have 0.9995 probability that at most 4 light bulbs are defective.

6 0
3 years ago
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inysia [295]
Donny is correct. To solve this problem all you need to do is add 35 to 15 equation below ⬇️

4 0
2 years ago
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