
The unknown b is stuck in the exponent position.
We can can fix that by using logarithms.
Log is the inverse operation of the exponential.
We'll take log of each side.
Log of what base tho?
Well, the base of our exponential is e,
so we'll take log base e of each side.

We'll apply one of our log rules next:

This allows us to take the exponent out of the log,

Another thing to remember about logs:
When the base of the log matches the inside of the log,
then the whole thing is simply 1,



So our equation simplifies to this,

As a final step, divide both sides by 3,

k, hope that helps!
1.111.... so just right 1.2
A quotient of 3 with 28 as a remainder means that 43 fits inside our number 3 times, and you have 28 more units as a remainder.
So, our number is

To write another division problem that has a quotient of 3 and a remainder of 28, we simply choose another number to substitute 43 in the expression above. For example, if we choose 100, the expression becomes

Which means that 328 has quotient of 3 with 28 as a remainder when divided by 100.