-12 + 18 = 70 - 64 or(-12+18)+(6*12)-2
Answer:
It's position at time t = 5 is 593.
Step-by-step explanation:
The velocity v(t) is the integral of the acceleration a(t)
The position s(t) is the integral of the velocity v(t)
We have that:
The acceleration is:
Velocity:
K is the initial velocity, that is v(0). Since V(0) = 13, K = 13
Then
Position:
Since s(0) = 3
What is its position at time t=5?
This is s(5).
It's position at time t = 5 is 593.
∠1 is an angle formed by the two lines PF and YF at point F
We can also call this angle as ∠PFY because it indicates the point F in the middle where the angle is formed
We can call this angle as ∠YFP because it also indicates the point F in the middle where the angle is formed
we can also call this angle ∠F since F is the point where the angle is formed.
Correct answer: ∠PFY, ∠YFP, ∠F
Answer: 120[4(x^6 + x^3 + x^4 + x) +7(x^7 + x^4 + x^5 + x^2)]
Step-by-step explanation:
=24x(x^2 + 1)4(x^3 + 1)5 + 42x^2(x^2 + 1)5(x^3 + 1)4
Remove the brackets first
=[(24x^3 +24x)(4x^3 + 4)]5 + [(42x^4 +42x^2)(5x^3 + 5)4]
=[(96x^6 + 96x^3 +96x^4 + 96x)5] + [(210x^7 + 210x^4 + 210x^5 + 210x^2)4]
=(480x^6 + 480x^3 + 480x^4 + 480x) + (840x^7 + 840x^4 + 840x^5 + 840x^2)
Then the common:
=[480(x^6 + x^3 + x^4 + x) + 840(x^7 + x^4 + x^5 + x^2)]
=120[4(x^6 + x^3 + x^4 + x) +7(x^7 + x^4 + x^5 + x^2)]
All except combine like terms. Since you only have 1 variable.
Hope this helps.
r3t40
