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photoshop1234 [79]
4 years ago
12

A number divided by 43 has a quotient of 3 with 28 as a remainder. Find the number. Show your work. Write another division probl

em that has a quotient of 3 and a remainder of 28.
Mathematics
1 answer:
antiseptic1488 [7]4 years ago
4 0

A quotient of 3 with 28 as a remainder means that 43 fits inside our number 3 times, and you have 28 more units as a remainder.

So, our number is

3\times 43 + 28 = 129+28=157

To write another division problem that has a quotient of 3 and a remainder of 28, we simply choose another number to substitute 43 in the expression above. For example, if we choose 100, the expression becomes

3\times 100 + 28 = 300+28=328

Which means that 328 has quotient of 3 with 28 as a remainder when divided by 100.

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Given sin(−θ)=−1/6 and tanθ=−√35/35 What is the value of cosθ?
murzikaleks [220]

Answer:

cos(\theta)=-\frac{\sqrt{35} }{6}

Step-by-step explanation:

Recall the negative angle identity for the sine function:

sin(- \theta)=-sin(\theta)  

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sin(\theta)=-sin(-\theta)\\sin(\theta) =-(-\frac{1}{6} )\\sin(\theta)= \frac{1}{6}

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tan(\theta)=\frac{sin(\theta)}{cos(\theta)}\\-\frac{\sqrt{35} }{35} =\frac{1/6}{cos(\theta)} \\cos(\theta)=-\frac{\frac{1}{6} }{\frac{\sqrt{35} }{35} } \\cos(\theta)=-\frac{35}{6\,\sqrt{35} } \\cos(\theta)=-\frac{\sqrt{35} }{6}

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3 years ago
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VMariaS [17]
To be divisible by 63, it must be divisible by both 7 and 9, since 7x9 = 63.  Factor the expression, simplify, and see if both 7 and 9 are factors, which would make it divisible by both 7 and 9. (163 - 83)(43 + 23) = [(24)3 - (23)3] [(22)3 + 23] = (212 - 29)(26 + 23) = [29(23 - 1)] [23(23 + 1)] = [29(8 - 1)] [23(8 + 1)] = 29(7) 23 (9) = 63(212) It is a multiple of 63, and hence divisible by 63.
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3 years ago
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