we can see that the center is (-3, 3) and the radius is 9 units.
<h3 /><h3>
How to find the center and radius of the circle?</h3>
The general circle equation, for a circle with a center (a, b) and radius R is given by:
(x - a)^2 + (y - b)^2 = R^2
Here we have the equation:
x^2 + y^2 + 6x = 6y + 63
Let's complete squares:
x^2 + y^2 + 6x - 6y = 63
(x^2 + 6x) + (y^2 - 6y) = 63
(x^2 + 2*3x) + (y^2 - 2*3y) = 63
Now we can add and subtract 9, (two times) so we get:
(x^2 + 2*3x + 9) - 9 + (x^2 - 2*3x + 9) - 9 = 63
(x + 3)^2 + (y - 3)^2 = 63 + 9 + 9 = 81 = 9^2
(x + 3)^2 + (y - 3)^2 = 9^2
Comparing with the general circle equation, we can see that the center is (-3, 3) and the radius is 9 units.
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The height of the kite will be 53.32 feet above the ground.
<h3>What is trigonometry?</h3>
The branch of mathematics sets up a relationship between the sides and the angles of the right-angle triangle is termed trigonometry.
Given that:-
- The boy is flying a kite, holding his hands a distance of 3.5 feet above the ground and
- letting all the kite's strings play out. He measures the angle of elevation from his hand to the kite to be 29°. If the string from the kite to his hand is 110 feet long, what is the total vertical height?
The height of the kite above the ground will be calculated as:-


H = Sin(29) x 110
H = 53.32 feet
The hand of the boy is 3.5 above the ground so the total height H(t) of the kite above the ground will be:-
H(t) = 53.232 + 3.5
H(t) = 56.28 feet.
Therefore the height of the kite will be 53.32 feet above the ground.
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4,3,2,1,0,-1, -2, -3, -4,
Answer:
thanks for the points
Step-by-step explanation:
also
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Answer:
Basketball court is half mile away and the distance between pool and basketball court is 1 mile.