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Vladimir [108]
3 years ago
5

a card is drawn at random from a standard 52 card deck has a 1/13 chance of being at 8. What is the probability of the car not b

eing an ace?​

Mathematics
2 answers:
Galina-37 [17]3 years ago
7 0

Answer:

\frac{12}{13}

Answer D is correct

Step-by-step explanation:

there \:  \:  \: are = 52 \:  \: cards   \\ aces \: \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:   = 4 \:  \: cards \\ not \: aces \:  \:  \:  \:  \:  = 52 - 4 \\  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  = 48 \\ p  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  =  \frac{48}{52}  \\   \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: =  \frac{12}{13}

hope this helps

brainliest appreciated

good luck! have a nice day!

Free_Kalibri [48]3 years ago
5 0

Answer:

12/13

Step-by-step explanation:

There are 52 cards in the deck

4 are aces

That leaves 52-4  or 48 that are not aces

P(not an aces) = cards that are not aces / total

                        = 48/52

                       =12/13

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