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Vladimir [108]
2 years ago
5

a card is drawn at random from a standard 52 card deck has a 1/13 chance of being at 8. What is the probability of the car not b

eing an ace?​

Mathematics
2 answers:
Galina-37 [17]2 years ago
7 0

Answer:

\frac{12}{13}

Answer D is correct

Step-by-step explanation:

there \:  \:  \: are = 52 \:  \: cards   \\ aces \: \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:   = 4 \:  \: cards \\ not \: aces \:  \:  \:  \:  \:  = 52 - 4 \\  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  = 48 \\ p  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  =  \frac{48}{52}  \\   \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: =  \frac{12}{13}

hope this helps

brainliest appreciated

good luck! have a nice day!

Free_Kalibri [48]2 years ago
5 0

Answer:

12/13

Step-by-step explanation:

There are 52 cards in the deck

4 are aces

That leaves 52-4  or 48 that are not aces

P(not an aces) = cards that are not aces / total

                        = 48/52

                       =12/13

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Bill is traveling south and drives 45 miles per hour.
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Answer:

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Step-by-step explanation:

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1.) Solve x - 9 = -12<br>-) Solve 2t + 7 = -1​
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malfutka [58]

Answer:

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3 0
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A recent survey showed that in a sample of 100 elementary school teachers, 15 were single. In a sample of 180 high school teache
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Answer:

By using hypothesis test at α = 0.01, we cannot conclude that the proportion of high school teachers who were single greater than the proportion of elementary teachers who were single

Step-by-step explanation:

let p1  be the proportion of elementary teachers who were single

let p2 be the proportion of high school teachers who were single

Then, the null and alternative hypotheses are:

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We need to calculate the test statistic of the sample proportion for elementary teachers who were single.

It can be calculated as follows:

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Using the numbers, we get

\frac{0.2-0.15}{\sqrt{\frac{0.15*0.85}{180} } } ≈ 1.88

Using z-table, corresponding  P-Value is ≈0.03

Since 0.03>0.01 we fail to reject the null hypothesis. (The result is not significant at α = 0.01)

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