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4 years ago

Which number has the least absolute value? A) 30 B) 10 C) −20 D) −40

Mathematics

2 answers:

djverab [1.8K]4 years ago

8 0

Answer:

Step-by-step explanation:

ExtremeBDS [4]4 years ago

3 0

Answer:-40

Step-by-step explanation:

Because that means below 0

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angle of depression is 28 degrees, the tower is 120 feet tall how far is the base of the tower is the plane

Simora [160]

Answer:

160

Step-by-step explanation:

because you have to count the degree of the tower so keep adding up then u get 160 which is the correct answer

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3 years ago

Each student was asked to create an expression whose quotient is 1/3. Each student and their response can be seen in the table b

scoray [572]

Answer:

Pretty sure its Chris

Step-by-step explanation:

I've done this work and the only one with the answer is him.

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4 years ago

Suppose that 50% of all young adults prefer McDonald's to Burger King when asked to state a preference. A group of 12 young adul

ddd [48]

Answer:

a) 0.194 = 19.4% probability that more than 7 preferred McDonald's

b) 0.787 = 78.7% probability that between 3 and 7 (inclusive) preferred McDonald's

c) 0.787 = 78.7% probability that between 3 and 7 (inclusive) preferred Burger King

Step-by-step explanation:

For each young adult, there are only two possible outcomes. Either they prefer McDonalds, or they prefer burger king. The probability of an adult prefering McDonalds is independent from other adults. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

50% of all young adults prefer McDonald's to Burger King when asked to state a preference.

This means that $p = 0.5$

12 young adults were randomly selected

This means that $n = 12$

(a) What is the probability that more than 7 preferred McDonald's?

$P(X > 7) = P(X = 8) + P(X = 9) + P(X = 10) + P(X = 11) + P(X = 12)$

In which

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 8) = C_{12,8}.(0.5)^{8}.(0.5)^{4} = 0.121$

$P(X = 9) = C_{12,9}.(0.5)^{9}.(0.5)^{3} = 0.054$

$P(X = 10) = C_{12,10}.(0.5)^{10}.(0.5)^{2} = 0.016$

$P(X = 11) = C_{12,11}.(0.5)^{11}.(0.5)^{1} = 0.003$

$P(X = 12) = C_{12,12}.(0.5)^{12}.(0.5)^{0} = 0.000$

$P(X > 7) = P(X = 8) + P(X = 9) + P(X = 10) + P(X = 11) + P(X = 12) = 0.121 + 0.054 + 0.016 + 0.003 + 0.000 = 0.194$

0.194 = 19.4% probability that more than 7 preferred McDonald's

(b) What is the probability that between 3 and 7 (inclusive) preferred McDonald's?

$P(3 \leq X \leq 7) = P(X = 3) + P(X = 4) + P(X = 5) + P(X = 6) + P(X = 7)$

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 3) = C_{12,3}.(0.5)^{3}.(0.5)^{9} = 0.054$

$P(X = 4) = C_{12,4}.(0.5)^{4}.(0.5)^{8} = 0.121$

$P(X = 5) = C_{12,5}.(0.5)^{5}.(0.5)^{7} = 0.193$

$P(X = 6) = C_{12,6}.(0.5)^{6}.(0.5)^{6} = 0.226$

$P(X = 7) = C_{12,7}.(0.5)^{7}.(0.5)^{5} = 0.193$

$P(3 \leq X \leq 7) = P(X = 3) + P(X = 4) + P(X = 5) + P(X = 6) + P(X = 7) = 0.054 + 0.121 + 0.193 + 0.226 + 0.193 = 0.787$

0.787 = 78.7% probability that between 3 and 7 (inclusive) preferred McDonald's

(c) What is the probability that between 3 and 7 (inclusive) preferred Burger King?

Since $p = 1-p = 0.5$ , this is the same as b) above.

0.787 = 78.7% probability that between 3 and 7 (inclusive) preferred Burger King

7 0

3 years ago

How do you solve this 3.7÷(1 2/9 −0.4)?

lara31 [8.8K]

3.7÷(1 2/9 −0.4) = 166.5/45 ÷ 37/45 = 4.5

0.4 = 40/100 = 2/5

2/5 = 18/45

1 2/9 = 11/9 = 55/45

55/45 - 18/45 = 37/45

3.7 = 370/100 = 18.5/5 = 166.5/45

ANSWER: 4.5

8 0

4 years ago

Read 2 more answers

Instructions

Naya [18.7K]

Answer:

yes

Step-by-step explanation:

youre trying to find when -1/4x + 3/2 = -x+ 3

so if you set it up like that and then solve for x you get 2

then, you know that 2 is your x value so just plug in x into one of the equations to get the y value

(i used -x+3 bc its easier)

-2+3=y

y= 1

so your solution is (2,1)

also heres the graph

5 0

3 years ago