The answer is x-18
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Answer:
10 number of checks.
Cost = $6
Step-by-step explanation:
Given that:
Fixed Charges of first bank = $5
Charges of first bank per check = $0.10
Fixed Charges of second bank = $4
Charges of second bank per check = $0.20
To find:
Number of checks such that the charges for the banks become the same?
Solution:
Let the number of checks = 
Cost for the first bank for checks = $5 + $0.10
Cost for the second bank for checks = $4 + $0.20
As per question statement, both the costs are the same.
Comparing the values:
So, for 10 number of checks the cost will be same.
The cost = 4 + 0.20 
10 = <em>$6</em>
1 Factor completely.
p2+7p+10 = (p + 5)(p + 2)
2 Factor completely.
x2+10x+16 = (x + 4)(x + 6)
3 Factor completely.
x2+7x−18 = (x + 9)(x - 2)
4 Factor completely.
x2−5x−24 = (x - 8)(x + 3)
5 Factor completely.
x2−3x−40 = (x - 8)(x + 5)
Both the points have a coordinate where y is -1, so the equation is simply -1
y=-1
however if you wanted to really show the working out, it looks like this:
y=mx+c
m=change in y/change in x
m=(-1-1)/(-5+0)=0
subsitute one of the coordinates into y=mx+c
-1=0+c
c=-1
so then y=-1
Answer:
35% or 35/100
Step-by-step explanation:
Gage Millar, Algebra 2 tutor
Choosing a number LESS than (not equal to 8) is 7/10 (1,2,3,4,5,6,7)
Chosing an even number is 5/10 (2,4,6,8,10)
so just multiply 7/10 x 5/10 to get 35 over 100, or a 35% chance
