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mrs_skeptik [129]
3 years ago
13

Can someone solve the hypotenuse for me? Thank you!

Mathematics
1 answer:
dmitriy555 [2]3 years ago
3 0

Answer:

Side a = 88.67626

Side b = 57

Side c = 67.92995

Angle ∠A = 90° = 1.5708 rad = π/2

Angle ∠B = 40° = 0.69813 rad = 2/9π

Angle ∠C = 50° = 0.87266 rad = 5/18π

Area = 1,936.00371

Perimeter p = 213.60621

Semiperimeter s = 106.80311

Height ha = 43.66453  

Height hb = 67.92995

Height hc = 57

Median ma = 44.33813  

Median mb = 73.66633

Median mc = 66.35224

Inradius r = 18.12685  

Circumradius R = 44.33813  

Vertex coordinates: A[0, 0] B[67.92995, 0] C[0, 57]

Centroid: [22.64332, 19]

Inscribed Circle Center: [18.12685, 18.12685]

Circumscribed Circle Center: [33.96498, 28.5]

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Firdavs [7]

y-3=4

 +3 +3

y=7

Dude, this is easy

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4 0
3 years ago
a box in the shapr of s rectangular prism has a length of 3 5/8 inches, a width of 2 1/2 inches and a height of 4 inches. what i
Sergeeva-Olga [200]

Answer:

V = 36 1/4 in.^3

Step-by-step explanation:

V = LWH

L = 3 5/8 in.

W = 2 1/2 in.

H = 4 in.

V = (3 5/8)(2 1/2)(4) in.^3

Change the mixed numerals to fractions.

<em>To change the mixed numeral a b/c to a fraction, do this: </em>

<em>a b/c = (ac + b)/c</em>

V = (3 * 8 + 5)/8 * (2 * 2 + 1)/2 * 4/1

V = (24 + 5)/8 * (4 + 1)/2 * 4/1

V = 29/8 * 5/2 * 4/1 in.^3

V = 580/16 in.^3

V = 145/4 in.^3

V = 36 1/4 in.^3

4 0
3 years ago
Find the area of the figure. please help my teacher is waiting.......
katrin [286]

Answer:

The area of the shape is 89m²

Step-by-step explanation:

You need to subtract the area of the empty triangle from the area of the rectangle.

The rectangle's area is 13m × 8m = 104m²

The triangle's area is (6m × (13 - 8)m) / 2 = (6 × 5) / 2 m² = 15m²

Subtract the triangle's area from the rectangle:

104m² - 15m²

= 89m²

7 0
2 years ago
C
Pepsi [2]

Answer:lazy

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Which coefficient matrix represents a system of linear equations that has a unique solution ?
finlep [7]

Answer:

Option C

Step-by-step explanation:

We are given a coefficient matrix along and not the solution matrix

Since solution matrix is not given we cannot check for infinity solutions.

But we can check whether coefficient matrix is 0 or not

If coefficient matrix is zero, the system is inconsistent and hence no solution.

Option A)

|A|=\left[\begin{array}{ccc}4&2&6\\2&1&3\\-2&3&-4\end{array}\right] =0

since II row is a multiple of I row

Hence no solution or infinite

OPtion B

|B|=\left[\begin{array}{ccc}2&0&-2\\-7&1&5\\4&-2&0\end{array}\right] \\=2(10)-2(10)=0

Hence no solution or infinite

Option C

\left[\begin{array}{ccc}6&0&-2\\-2&0&6\\1&-2&0\end{array}\right] \\=2(36-2)=68

Hence there will be a unique solution

Option D

\left[\begin{array}{ccc}5&10&5\\4&1&4\\-1&-2&-1\end{array}\right] \\=2(10)-2(10)=0=0

(since I row is -5 times III row)

Hence there will be no or infinite solution

Option C is the correct answer



4 0
3 years ago
Read 2 more answers
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