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Anni [7]
2 years ago
11

Analyn is heating a solution in her chemistry lab.The temperature of the solution starts at 10 C. she turns on the burner and fi

nds that the solutions temperature increases by 4 C every minute. This graph shows the temperature change.

Mathematics
2 answers:
natita [175]2 years ago
5 0

Answer:

It's D

Step-by-step explanation:

Savatey [412]2 years ago
4 0

Answer:

22,3 is the answer to the question

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Find two numbers if their ratio is 9:11 and their difference is 6.
balu736 [363]

Answer:

27:33

Step-by-step explanation:

If u multiply both sides of the ratio by the same number, u get an equivalent ratio. By multiplying 9:11 by 3 on both sides, you get 27:33. The difference refers to subtraction. 33-27= 6 which is the difference between the two numbers.

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Hope this helps again! :)

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I WILL GIVE YOU 100 POINTS IF YOU HELP ME ON THIS PLEASE ASAP!
ValentinkaMS [17]

Answer:

4

Step-by-step explanation:

As I stated, the formula of the area of a triangle is LW/2.

Meaing all you have to do is 4x2/2.

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3 years ago
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Eddi Din [679]

Answer:

-2, 4

-1, -2

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2 years ago
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If a ball is thrown straight up into the air with an initial velocity of 70 ft/s, its height in feet after t seconds is given by
Vitek1552 [10]

Answer:

a) Average velocity at 0.1 s is 696 ft/s.

b) Average velocity at 0.01 s is 7536 ft/s.

c) Average velocity at 0.001 s is 75936 ft/s.

Step-by-step explanation:

Given : If a ball is thrown straight up into the air with an initial velocity of 70 ft/s, its height in feet after t seconds is given by y = 70t-16t^2.

To find : The average velocity for the time period beginning when t = 2 and lasting.  a. 0.1 s. , b. 0.01 s. , c. 0.001 s.

Solution :    

a) The average velocity for the time period beginning when t = 2 and lasting 0.1 s.

(\text{Average velocity})_{0.1\ s}=\frac{\text{Change in height}}{0.1}

(\text{Average velocity})_{0.1\ s}=\frac{h_{2.1}-h_2}{0.1}

(\text{Average velocity})_{0.1\ s}=\frac{(70(2.1)-16(2.1)^2)-(70(0.1)-16(0.1)^2)}{0.1}

(\text{Average velocity})_{0.1\ s}=\frac{69.6}{0.1}

(\text{Average velocity})_{0.1\ s}=696\ ft/s

b) The average velocity for the time period beginning when t = 2 and lasting 0.01 s.

(\text{Average velocity})_{0.01\ s}=\frac{\text{Change in height}}{0.01}

(\text{Average velocity})_{0.01\ s}=\frac{h_{2.01}-h_2}{0.01}

(\text{Average velocity})_{0.01\ s}=\frac{(70(2.01)-16(2.01)^2)-(70(0.01)-16(0.01)^2)}{0.01}

(\text{Average velocity})_{0.01\ s}=\frac{75.36}{0.01}

(\text{Average velocity})_{0.01\ s}=7536\ ft/s

c) The average velocity for the time period beginning when t = 2 and lasting 0.001 s.

(\text{Average velocity})_{0.001\ s}=\frac{\text{Change in height}}{0.001}  

(\text{Average velocity})_{0.001\ s}=\frac{h_{2.001}-h_2}{0.001}

(\text{Average velocity})_{0.001\ s}=\frac{(70(2.001)-16(2.001)^2)-(70(0.001)-16(0.001)^2)}{0.001}

(\text{Average velocity})_{0.001\ s}=\frac{75.936}{0.001}

(\text{Average velocity})_{0.001\ s}=75936\ ft/s

5 0
3 years ago
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