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expeople1 [14]
3 years ago
6

Help!! I have no clue how to do this

Mathematics
2 answers:
uranmaximum [27]3 years ago
7 0
A triangle equals 180° so set up the equation as
58+73+12x+1=180
132+12x=180 (I got 132 by adding 58,73,1)
Subtract 132 from both sides
You should get 12x=48
Divide both sides by 12
X=4
Fed [463]3 years ago
6 0
The sum of all the angles in a triangle is 180°.

(12x + 1) + 58° + 73° = 180°

12x + 132° = 180°

12x = 180° - 132°

x = 48°/12

x = 4°
You might be interested in
I need help.................
Yanka [14]

Answer:

-33 and -21

Step-by-step explanation:

-36, <u>-33</u>, -30, -27, -24, <u>-21</u>, -18

-36

-36 + 3 = -33

-33 + 3 = -30

-30 + 3 = -27

-27 + 3 = -24

-24 + 3 = -21

-21 + 3 = -18

8 0
2 years ago
A professor finds that the average SAT score among all students attending his college is 1150 ± 150 (μ ± σ). He polls his class
solniwko [45]

Answer:

Step-by-step explanation

Hello!

Be X: SAT scores of students attending college.

The population mean is μ= 1150 and the standard deviation σ= 150

The teacher takes a sample of 25 students of his class, the resulting sample mean is 1200.

If the professor wants to test if the average SAT score is, as reported, 1150, the statistic hypotheses are:

H₀: μ = 1150

H₁: μ ≠ 1150

α: 0.05

Z= \frac{X[bar]-Mu}{\frac{Sigma}{\sqrt{n} } } ~~N(0;1)

Z_{H_0}= \frac{1200-1150}{\frac{150}{\sqrt{25} } } = 1.67

The p-value for this test is  0.0949

Since the p-value is greater than the level of significance, the decision is to reject the null hypothesis. Then using a significance level of 5%, there is enough evidence to reject the null hypothesis, then the average SAT score of the college students is not 1150.

I hope it helps!

7 0
3 years ago
Which number line shows x = -5/2 y=3/4
allsm [11]
The graph would be A
5 0
3 years ago
Which complex number will be located above the real axis and to the left of the imaginaty axis
larisa86 [58]

Answer:

Step-by-step explanation:

4i − 1 Should be the answer Im so sorry if Im wrong

8 0
3 years ago
Shuffle a standard deck of playing cards and deal one card. define events j
grandymaker [24]
The question is missing some parts. To complete, J is the event of getting a jack and R is getting a red card.

The first question is to look for the P (J) and P (R) =
P (J) = 4/52 = 0.077; since there are only 4 jacks in a standard deck.

P (R) = 26/52 = 0.5; 26 because there are 13 each for diamonds and hearts.

The second question is to describe the event J and R in words. Then look for that event’s probability.

The card is a red jack or the card is red and a jack. P (J and R) = 2/52 = 0/038

The last question is explain why P (J or R) is not equal to P (J) + P (R). Then use the general addition rule to compute for P (J or R).

The event card is red and card is jack are not mutually exclusive meaning two or more events can happen simultaneously.  Thus one will count two cards twice unless using the general probability addition formula.

The probability for P (J ∪ R) is:P (J ∪ R) = 2 + 2 + 24 / 52 = 28/52 = 0.0538Or the other solution would be:P (J ∪ R) = 4/52 + 26/52 + 2/52 = 28/52 = 0.0538
7 0
3 years ago
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