For this case we have the following vertices:
A (-1,1) --------> A '(3, -1)
B (-2.1)
C (-1,4)
We note that the translation rule is:
(x, y) -----------> (x + 4, y-2)
Applying the translacion rule we have:
B (-2, 1) -----------> (-2 + 4, 1-2) ------> B '(2, -1)
C (-1, 4) -----------> (-1 + 4, 4-2) ------> C '(3, 2)
Answer:
The image of vertex B or the image of Vertex C are:
B '(2, -1)
C '(3, 2)
Wouldn't the formula be a×b/2?
Since A (area of circle = C) is given = 148
Where we assume:
Y represents radius of the circle (r)
X represents diameter of the circle (D)
Pi (π) = 3.14
A = 2 * π * y
148 = 2 * 3.14 * y
148 = 6.28 * y
y = 148/6.28
So, y = 23.56
D = 2 * y
D = 2 * 23.56
So, D = 47.12
Assume A is unknown (not given as 148)
A = π * y^2
A = 3.14 * (23.56)^2
A = 3.14 * 47.12
So, A = 147.95 (approx. A = 148)
