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3 years ago

Rachel is about to serve and tosses

Mathematics

1 answer:

grin007 [14]3 years ago

8 0

Answer:

b po

Step-by-step explanation:

try kopo isearch mamaya sa mama ko

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Find two consecutive odd integers whos sun is 116

sattari [20]

The two consecutive odd integers are 57 & 59.

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3 years ago

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The sum of 5 times a number and 4 is equal to 6

g100num [7]

Answer:

5(x+4)=6

5 times a number and (+) 4 is equal to 6.

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3 years ago

A new company spent $9,399.74 on 24 tablets for their employees. How much did each tablet cost? Round your answer to the nearest

Nitella [24]

$391.655 or $391.66 per table

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3 years ago

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I have k quarters, five less quarters than nickels and one more than twice as many dimes as quarters. Find the value of the coin

Alenkinab [10]

Answer:

(35k + 20) cents

Step-by-step explanation:

First of all, let us have the value of each unit:

1 quarter = 25 cents

1 nickel = 5 cents

1 dime = 10 cents

Given that number of quarter = k

Quarters are 5 lesser than Nickels, so number of nickels = k+5

One more than twice as many dimes as quarters:

k = 2 $\times$ Number of Dimes + 1

So, number of dimes = $\frac{1}{2}(k-1)$

Value of quarters = $25 \times k$ cents

Value of nickels = $5 \times (k+5) = (5k+25)\ cents$

Value of dimes = $\frac{1}{2}(k-1) \times 10 = (5k-5)\ cents$

So, total value of coins =

$25k + 5k +25 +5k-5\\\Rightarrow (35k+20)\ cents$

5 0

3 years ago

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If (ax+2)(bx+7)=15x2+cx+14 for all values of x, and a+b=8, what are the 2 possible values fo c

dolphi86 [110]

Given:

$(ax+2)(bx+7)=15x^2+cx+14$

And

$a+b=8$

Required:

To find the two possible values of c.

Explanation:

Consider

$\begin{gathered} (ax+2)(bx+7)=15x^2+cx+14 \\ abx^2+7ax+2bx+14=15x^2+cx+14 \end{gathered}$

$\begin{gathered} ab=15-----(1) \\ 7a+2b=c \end{gathered}$

And also given

$a+b=8---(2)$

Now from (1) and (2), we get

$\begin{gathered} a+\frac{15}{a}=8 \\ \\ a^2+15=8a \\ \\ a^2-8a+15=0 \end{gathered}$ $a=3,5$

Now put a in (1) we get

$\begin{gathered} (3)b=15 \\ b=\frac{15}{3} \\ b=5 \\ OR \\ b=\frac{15}{5} \\ b=3 \end{gathered}$

We can interpret that either of a or b are equal to 3 or 5.

When a=3 and b=5, we have

$\begin{gathered} c=7(3)+2(5) \\ =21+10 \\ =31 \end{gathered}$

When a=5 and b=3, we have

$\begin{gathered} c=7(5)+2(3) \\ =35+6 \\ =41 \end{gathered}$

Final Answer:

The option D is correct.

31 and 41

8 0

1 year ago