Answer:
A. 8.66 feet
B. 12.59 feet
C. Area of triangle when
is 129.9 square feet. Area of triangle when
is 188.85 square feet. Increasing the angle
increases the area.
Step-by-step explanation:
The equation that models the height of the triangle is:

Where,
is the height, and
is the angle
A.
When
, the height is:

B. When ![\theta=40[/tex\ , the height is:[tex]y=15Tan40\\y=12.59](https://tex.z-dn.net/?f=%5Ctheta%3D40%5B%2Ftex%5C%20%2C%20the%20%3Cstrong%3Eheight%3C%2Fstrong%3E%20is%3A%3C%2Fp%3E%3Cp%3E%5Btex%5Dy%3D15Tan40%5C%5Cy%3D12.59)
C. <em>To find the area of the isosceles triangular shaped garden, we use the </em><em>formula for the area of the triangle</em><em>:</em>

Where,
- A is the area
- b is the base, which is given as 30 feet, and
- h is the height [8.66 feet when the angle is 30 & 12.59 when angle is 40]
<u>When Vance uses
, the area is</u>:
square feet
<u>When Vance uses
, the area is</u>:
square feet
So we see that when the angle is more, the area is also more.
Answer: x = 8
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I'm going to use the notation log(2,x) to indicate "log base 2 of x". The first number is the base while the second is the expression inside the log (aka the argument of the log)
log(2,x) + log(2,(x-6)) = 4
log(2,x*(x-6)) = 4
x*(x-6) = 2^4
x*(x-6) = 16
x^2-6x = 16
x^2-6x-16 = 0
(x-8)(x+2) = 0
x-8 = 0 or x+2 = 0
x = 8 or x = -2
Recall that the domain of log(x) is x > 0. So x = -2 is not allowed. The same applies to log(2,x) as well.
Only x = 8 is a proper solution.
------------------------
You can use the change of base rule to check your work
log base 2 of x = log(2,x) = log(x)/log(2)
log(2,(x-6)) = log(x-6)/log(2)
So,
(log(x)/log(2)) + (log(x-6)/log(2)) = 4
(log(8)/log(2)) + (log(8-6)/log(2)) = 4
(log(8)/log(2)) + (log(2)/log(2)) = 4
(log(2^3)/log(2)) + (log(2)/log(2)) = 4
(3*log(2)/log(2)) + (log(2)/log(2)) = 4
3+1 = 4
4 = 4
The answer is confirmed
5x = 26 + 1
5x = 27
x = 27/5
Answer: A) or the first option ✅
Answer:
- Yes, diagonals bisect each other
Step-by-step explanation:
<em>See attached</em>
Plot the points on the coordinate plane
Visually, it is seen that the diagonals bisect each other.
We can prove this by calculating midpoints of AC and BD
<u>Midpoint of AC has coordinates of:</u>
- x = (1 - 1)/2 = 0
- y = (4 - 4)/2 = 0
<u>Midpoint of BD has coordinates of:</u>
- x = (4 - 4)/2 = 0
- y = (-1 + 1)/2 = 0
As per calculations the origin is the bisector of the diagonals.