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sergiy2304 [10]
3 years ago
14

Please answer question 10

Mathematics
1 answer:
insens350 [35]3 years ago
7 0

Answer:

Where is the graph?

Step-by-step explanation:

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Each letter from the word MATHEMATICS is written on a separate slip of paper. The 11th slips of paper are placed in a hat and tw
amid [387]
It may be possibly 4 out of 9
6 0
3 years ago
Vance is designing a garden in the shape of an isosceles triangle. The base of the garden is 30 feet long. The function y = 15 t
Stella [2.4K]

Answer:

A. 8.66 feet

B. 12.59 feet

C. Area of triangle when \theta=30  is 129.9 square feet. Area of triangle when \theta=40 is 188.85 square feet. Increasing the angle  \theta  increases the area.


Step-by-step explanation:

The equation that models the height of the triangle is:

y=15 Tan \theta

Where,

  • y is the height, and
  • \theta  is the angle

A.

When \theta=30 , the height is:

y=15Tan30\\y=8.66


B. When \theta=40[/tex\ , the height is:[tex]y=15Tan40\\y=12.59


C. <em>To find the area of the isosceles triangular shaped garden, we use the </em><em>formula for the area of the triangle</em><em>:</em>

A=\frac{1}{2}bh

Where,

  • A is the area
  • b is the base, which is given as 30 feet, and
  • h is the height [8.66 feet when the angle is 30 & 12.59 when angle is 40]

<u>When Vance uses \theta=30 , the area is</u>:

A=\frac{1}{2}(30)(8.66)\\A=129.9  square feet


<u>When Vance uses \theta=40 , the area is</u>:

A=\frac{1}{2}(30)(12.59)\\A=188.85  square feet


So we see that when the angle is more, the area is also more.

4 0
3 years ago
Read 2 more answers
Please show ALL work!<br><br> Solve for x: log₂x+log₂(x-6)=4
Vlad [161]
Answer: x = 8

---------------------------------------------
---------------------------------------------

I'm going to use the notation log(2,x) to indicate "log base 2 of x". The first number is the base while the second is the expression inside the log (aka the argument of the log)

log(2,x) + log(2,(x-6)) = 4
log(2,x*(x-6)) = 4
x*(x-6) = 2^4
x*(x-6) = 16
x^2-6x = 16
x^2-6x-16 = 0
(x-8)(x+2) = 0
x-8 = 0 or x+2 = 0
x = 8 or x = -2

Recall that the domain of log(x) is x > 0. So x = -2 is not allowed. The same applies to log(2,x) as well.

Only x = 8 is a proper solution.

------------------------

You can use the change of base rule to check your work
log base 2 of x = log(2,x) = log(x)/log(2)
log(2,(x-6)) = log(x-6)/log(2)

So,
(log(x)/log(2)) + (log(x-6)/log(2)) = 4
(log(8)/log(2)) + (log(8-6)/log(2)) = 4
(log(8)/log(2)) + (log(2)/log(2)) = 4
(log(2^3)/log(2)) + (log(2)/log(2)) = 4
(3*log(2)/log(2)) + (log(2)/log(2)) = 4
3+1 = 4
4 = 4
The answer is confirmed

5 0
3 years ago
Solve for x. <br><br> 5x - 1 = 26<br><br> x = 27/5<br> x = 5<br> x = -5
yan [13]
5x = 26 + 1
5x = 27
x = 27/5

Answer: A) or the first option ✅
4 0
3 years ago
100 POINTS FOR WHOEVER ANSWER THIS QUESTION FULLY!!!
natulia [17]

Answer:

  • Yes, diagonals bisect each other

Step-by-step explanation:

<em>See attached</em>

Plot the points on the coordinate plane

Visually, it is seen that the diagonals bisect each other.

We can prove this by calculating midpoints of AC and BD

<u>Midpoint of AC has coordinates of:</u>

  • x = (1 - 1)/2 = 0
  • y = (4 - 4)/2 = 0

<u>Midpoint of BD has coordinates of:</u>

  • x = (4 - 4)/2 = 0
  • y = (-1 + 1)/2 = 0

As per calculations the origin is the bisector of the diagonals.

7 0
3 years ago
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