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Alex
3 years ago
11

How do you solve this in system of equations in math! y=3x y=2+x

Mathematics
1 answer:
Elodia [21]3 years ago
5 0
U google it lol lol lol lol lol
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Evaluate 4/x for x = -2/3
KonstantinChe [14]

4/x where x= -2/3

4/(-2/3)

(4/1) / (-2/3)

(4/1) * (3/-2)

12/-2

-6

Hope this helps! :)

4 0
3 years ago
System of solution -x+2y=-6<br> 3x+2y=2
jok3333 [9.3K]

(16/3 1/3)

x=16/3 y=1/3

8 0
3 years ago
Read 2 more answers
When you factor an equation do you have to factor out the negative out of the final product
ozzi
Try -(x+6) if not then try (-x-6)
7 0
3 years ago
Suppose that wait times for customers at a grocery store cashier line are uniformly distributed between one minute and twelve mi
olchik [2.2K]

a) Mean: 6.5 min, variance: 10.1 min

b) 0.54 (54%)

c) 0.73 (73%)

d) 0.34

Step-by-step explanation:

a)

Here we can call X the variable indicating the waiting time for the customers:

X = waiting time

We are told that the waiting time is distributed uniformly between 1 and 12; this means that

1\leq X \leq 12

And the probability is equal for each value of X, so:

p(X=1)=p(X=2)=....=p(X=12)

The mean of a uniform distribution is given by:

E[X]=\frac{b+a}{2}

where a and b are the minimum and maximum values of the variable X. In this case,

a = 1

b = 12

So the mean value of X is

E[X]=\frac{12+1}{2}=6.5 (minutes)

The variance of a uniform distribution is given by:

Var[X]=\frac{1}{12}(b-a)^2

And substituting the values of this problem,

Var[X]=\frac{1}{12}(12-1)^2=10.1 (minutes)

b)

Since the distribution is uniform between 1 and 12, we can write the probability density function as

f(x)=\frac{1}{b-a}

The cumulative function gives the probability that the values of X is less than a certain value t:

p(X (1)

In this case, we want to find the probability that the waiting time is less than 7 minutes, so

t = 7

We also have:

a = 1

b = 12

Therefore, calculating (1) and substituting, we find:

p(X

c)

The probability that a customer waits between four and twenty minutes can be rewritten as

p(4

This can be written as:

p(4 (1)

However, the probabilty of X>4 can be written as

p(X>4)=1-p(X

Also, we notice that

p(X because the maximum value of X is 12; therefore, we can rewrite (1) as

p(4

We can calculate p(X by using the same method as in part b:

p(X

So, we find

p(4

d)

In this part, we know that a customer waits for

X = k

minutes in line, and he receives a coupon worth

0.2k^{\frac{1}{4}} dollars.

Here we want to find the mean of the coupon value.

Here therefore we have a new variables defined as

Y=0.2X^{\frac{1}{4}}

Given a variable with standard (between 0 and 1) uniform distribution X, the variable

Y=X^n

follows a beta distribution, with parameters (\frac{1}{n},1), and whose mean value is given by

E[Y]=\frac{1/n}{1+\frac{1}{n}}

In this case,

n=\frac{1}{4}

So the mean value of X^{1/4} is

E[X^{1/4}]=\frac{1/(1/4)}{1+\frac{1}{1/4}}=\frac{4}{1+4}=\frac{4}{5}=0.8

However, our variable is distribution is non-standard, because its values are between 1 and 12, so the range is

Min = 1^{1/4}=1\\Max =12^{1/4}=1.86

So, the actual mean value of X^{1/4} is

E[X^{1/4}]=0.8\cdot (1.86-1)+1=1.69

However, in the  definition of Y we also have a factor 0.2; therefore, the mean value of Y is

E[Y]=0.2E[X^{1/4}]=0.2\cdot 1.69 =0.34

5 0
3 years ago
Type the correct answer in each box.
IgorLugansk [536]

Answer:

m∠<em>DEB</em> = _<u>70</u>_°

m∠<em>BCD</em>= _<u>110</u>_°

m∠<em>EAB</em>= _<u>73</u>_°​

Step-by-step explanation:

<u>To find ∠</u><em><u>DEB</u></em><u>: </u>

Take the angle of ∠<em>EDC</em>, which is 110°. We know the total degree in a triangle is 180°. So, we do 180° - 110° to get 70°.

<u>To find ∠</u><em><u>BCD</u></em><u>: </u>

Because <em>EBCD</em> is an isosceles trapezoid, this means that ∠<em>D</em> and ∠<em>C</em> both have the congruent angles. Since we know ∠<em>EDC</em> is 110°, this means that ∠<em>C</em> is also 110°.

<u>To find ∠EAB: </u>

We know that m∠<em>ABC</em> is 133° and ∠<em>DEA</em> is 114°. However, both angles count both the triangle and trapezoid. Previously we figured out that ∠<em>DEB</em> is 70°. We'll take the angle of ∠<em>DEA</em> and subtract the angle of ∠<em>DEB</em> from it, which gets us 44°. To figure out the angle of ∠<em>B</em>, we take the angle of ∠<em>ABC</em> and subtract 70° or the angle of ∠<em>DEB</em>, which gets us 63°. Now we take the total degree of a triangle, 180° and minus both 44° and 63° from it, which is 73°.

- 2021 Edmentum

3 0
3 years ago
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