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drek231 [11]
3 years ago
8

F(x) at its minimum

Mathematics
1 answer:
morpeh [17]3 years ago
6 0

Hi there! :)

\large\boxed{x = -3}

Looking at the graph, the minimum y-value is the lowest point on the graph, or y = -2.

Find the x-value that corresponds to this y-coordinate:

f(x) = -2

f(-3) = -2

Therefore, the answer is B) -3.

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In an attempt to escape a desert island, a castaway builds a raft and sets out to sea. The wind shifts a great deal during the d
nikdorinn [45]

Answer:

R = 7,34 km

Ф = 63,43° north of east

Step-by-step explanation:

Let´s analyze each movement and find its perpendicular components. Then, we are going to add the components along the x and y axes to get the resultant and finally to calculate its magnitude and direction.

To determine the perpendicular components, we will use right triangles trigonometrics ratios.

Please see images for each displacement in attached file.

  • <u>Displacement A: 2.50 km and 45° north of west</u>

Ax= AcosФ = 2.50cos45° = 1.77 km (neg. direction)

Ay= AsenФ = 2.50sen45° = 1.77 km (pos. direction)

  • <u>Displacement B: 4.70 km and 60° south of east</u>

Bx= BcosФ = 4.70cos60° = 2,35 km (pos. direction)

By= BsenФ = 4.70sen60° = 4,07 km (neg. direction)

  • <u>Displacement C: 1.30 km and 25° south of west </u>

Cx= CcosФ = 1.30cos25° = 1,18 km (neg. direction)

Cy= CsenФ = 1.30sen25° = 0.55 km (neg. direction)

  • <u>Displacement D: 5.10 km due east (0°)</u>

Dx= DcosФ = 5.10 km (pos. direction)

Dy= DsenФ = 0 km

  • <u>Displacement E: 1.70 km and 5° east of north</u>

Ex= EsenФ = 1.70sen5° = 0,15 km (pos. direction)

Ey= EcosФ = 1.70cos5° = 1.69 km (pos. direction)

  • <u>Displacement F: 7.20 km and 55° south of west</u>

Fx= FcosФ = 7.20cos55° = 4.13 km (neg. direction)

Fy= FsenФ = 7.20sen55° = 5.90 km (neg. direction)

  • Displacement G: 2.80 km and 10° north of east

Gx= GcosФ = 2.80cos10° = 2.76 km (pos. direction)

Gy= GsenФ = 2.80sen10° = 0.49 km (pos. direction)

Now, we add the components along the x- and y- axis to find the components of the resultant (R):

Rx = Ax + Bx + Cx + Dx + Ex + Fx + Gx

Ry = Ay + By + Cy + Dy + Ey + Fy + Gy

Therefore,

Rx= (-1.77)+(2.35)+(-1.18)+(5.10)+(0.15)+(-4.13)+(2.76)

Ry= (1.77)+(-4.07)+(-0.55)+(0)+(1.69)+(-5.90)+(0.49)

<em>Note: minus (-) symbol to negative directions</em>

Rx = 3.28 km

Ry = - 6.57 km

Let´s use the Theorem of Pythagoras to find the magnitud ot the resultant:

R = \sqrt{Rx^{2} +Ry^{2} }

R =\sqrt{(3.28)^{2}+(-6.57)^{2} }

R = 7,34 km

To find the direction of the resultant:

tanФ = \frac{Ry}{Rx}

tanФ = \frac{6.57}{3.28}

tanФ = 2.00

Ф = tan-1 (2.00)

Ф = 63,43° north of east

Download pdf
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3 years ago
On Friday 32 students in mr. tankias class are each served 6 ounces of milk for lunch. Home many QUARTS of milk are served to th
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It would be 6 quarts of milk

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Find the slope of the line y = 5x + 4
Akimi4 [234]

Answer:

The slope is 5

Step-by-step explanation:

Slope is in place of the m hope this helps!

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2 years ago
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It takes my’khiyah 40 seconds to run 1/3 of a lap. How many laps can she run in 5 minutes
kakasveta [241]
Answer:
number of laps = 5/2 = 2.5 laps 

Explanation:
First, we will need to convert the minutes to seconds.
5 minutes = 5 * 60 = 300 seconds

Now, we know that she can run 1/3 of a lap in 40 seconds. To know the number of laps that she can run in 300 seconds, all we have to do is cross multiplication as follows:
40 seconds .................> 1/3 laps
300 seconds ................> ?? laps
number of laps = (300 * 1/3) / 40
number of laps = (100) / 40
number of laps = 5/2 = 2.5 laps

Hope this helps :)
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Can you solve -4a^ - (6a-2) + 3 (a^-1).the arrows that are pointing up is exponent 2.also please show work
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First step is to distribute.
-4a^2 - 6a +2 + 3a^2 -3
Combine like terms
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