I answered this recently.
Choices were:
A)Both m(x) and p(x) cross the x-axis at 7.
<span>B)Both m(x) and p(x) cross the y-axis at 7. </span>
<span>C)Both m(x) and p(x) have the same output value at x = 7. </span>
<span>D)Both m(x) and p(x) have a maximum or minimum value at x = 7.
</span>
The true statement was Choice C. Both m(x) and p(x) have the same output value at x = 7.<span> </span>
Answer:
7.68
Step-by-step explanation:
Just add them :)
Answer:
110 pages
Step-by-step explanation:
Day 1 =x
Day 2 =2x
Day 3 =x-6
(x)+(2x)+(x-6)=458
Add likes together.
4x-6=458
4x=464. Divide both sides by 4 to get x. X=116
Day 3=116-6=110
You have two choices.
The minimum possible cost to operate your bat factory for a day is $390,
and there are two quantities of bats that both cost that much.
One possibility:
Produce no bats at all per day. Zero. Nada. None.
Cost = 0.06(0)² - 7.2(0) + 390 = $390 per day.
The other choice:
Produce 120 bats per day.
Cost = 0.06(120²) - 7.2(120) + 390
= 0.06(14,400) - 7.2(120) + 390
= 864 - 864 + 390
= $390 per day.
If you produce any other number of bats in a day ... more than zero
but not 120 ... then it will cost you more than $390 to operate the factory
that day.
